Search (2 results, page 1 of 1)

  • × author_ss:"Akter, S."
  • × year_i:[2010 TO 2020}
  1. Akter, S.; D'Ambra, J.; Ray, P.: Trustworthiness in mHealth information services : an assessment of a hierarchical model with mediating and moderating effects using partial least squares (PLS) (2011) 0.00
    0.0012762066 = product of:
      0.0025524131 = sum of:
        0.0025524131 = product of:
          0.0051048263 = sum of:
            0.0051048263 = weight(_text_:s in 4136) [ClassicSimilarity], result of:
              0.0051048263 = score(doc=4136,freq=4.0), product of:
                0.05008241 = queryWeight, product of:
                  1.0872376 = idf(docFreq=40523, maxDocs=44218)
                  0.046063907 = queryNorm
                0.101928525 = fieldWeight in 4136, product of:
                  2.0 = tf(freq=4.0), with freq of:
                    4.0 = termFreq=4.0
                  1.0872376 = idf(docFreq=40523, maxDocs=44218)
                  0.046875 = fieldNorm(doc=4136)
          0.5 = coord(1/2)
      0.5 = coord(1/2)
    
    Source
    Journal of the American Society for Information Science and Technology. 62(2011) no.1, S.100-116
  2. D'Ambra, J.; Wilson, C.S.; Akter, S.: Application of the task-technology fit model to structure and evaluate the adoption of E-books by Academics (2013) 0.00
    0.0010635054 = product of:
      0.0021270108 = sum of:
        0.0021270108 = product of:
          0.0042540217 = sum of:
            0.0042540217 = weight(_text_:s in 529) [ClassicSimilarity], result of:
              0.0042540217 = score(doc=529,freq=4.0), product of:
                0.05008241 = queryWeight, product of:
                  1.0872376 = idf(docFreq=40523, maxDocs=44218)
                  0.046063907 = queryNorm
                0.08494043 = fieldWeight in 529, product of:
                  2.0 = tf(freq=4.0), with freq of:
                    4.0 = termFreq=4.0
                  1.0872376 = idf(docFreq=40523, maxDocs=44218)
                  0.0390625 = fieldNorm(doc=529)
          0.5 = coord(1/2)
      0.5 = coord(1/2)
    
    Source
    Journal of the American Society for Information Science and Technology. 64(2013) no.1, S.48-64