Search (3 results, page 1 of 1)

  • × author_ss:"Balog, K."
  • × author_ss:"Rijke, M. de"
  • × year_i:[2010 TO 2020}
  1. Hofmann, K.; Balog, K.; Bogers, T.; Rijke, M. de: Contextual factors for finding similar experts (2010) 0.02 
    0.016073458 = product of:
  0.032146916 = sum of:
    0.032146916 = product of:
      0.048220374 = sum of:
        0.04525219 = weight(_text_:k in 3456) [ClassicSimilarity], result of:
          0.04525219 = score(doc=3456,freq=4.0), product of:
            0.16225883 = queryWeight, product of:
              3.569778 = idf(docFreq=3384, maxDocs=44218)
              0.04545348 = queryNorm
            0.2788889 = fieldWeight in 3456, product of:
              2.0 = tf(freq=4.0), with freq of:
                4.0 = termFreq=4.0
              3.569778 = idf(docFreq=3384, maxDocs=44218)
              0.0390625 = fieldNorm(doc=3456)
        0.0029681858 = weight(_text_:s in 3456) [ClassicSimilarity], result of:
          0.0029681858 = score(doc=3456,freq=2.0), product of:
            0.049418733 = queryWeight, product of:
              1.0872376 = idf(docFreq=40523, maxDocs=44218)
              0.04545348 = queryNorm
            0.060061958 = fieldWeight in 3456, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              1.0872376 = idf(docFreq=40523, maxDocs=44218)
              0.0390625 = fieldNorm(doc=3456)
      0.6666667 = coord(2/3)
  0.5 = coord(1/2)
    Source
    Journal of the American Society for Information Science and Technology. 61(2010) no.5, S.994-1014
  2. Berendsen, R.; Rijke, M. de; Balog, K.; Bogers, T.; Bosch, A. van den: On the assessment of expertise profiles (2013) 0.01 
    0.011655438 = product of:
  0.023310876 = sum of:
    0.023310876 = product of:
      0.034966312 = sum of:
        0.031998128 = weight(_text_:k in 1089) [ClassicSimilarity], result of:
          0.031998128 = score(doc=1089,freq=2.0), product of:
            0.16225883 = queryWeight, product of:
              3.569778 = idf(docFreq=3384, maxDocs=44218)
              0.04545348 = queryNorm
            0.19720423 = fieldWeight in 1089, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              3.569778 = idf(docFreq=3384, maxDocs=44218)
              0.0390625 = fieldNorm(doc=1089)
        0.0029681858 = weight(_text_:s in 1089) [ClassicSimilarity], result of:
          0.0029681858 = score(doc=1089,freq=2.0), product of:
            0.049418733 = queryWeight, product of:
              1.0872376 = idf(docFreq=40523, maxDocs=44218)
              0.04545348 = queryNorm
            0.060061958 = fieldWeight in 1089, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              1.0872376 = idf(docFreq=40523, maxDocs=44218)
              0.0390625 = fieldNorm(doc=1089)
      0.6666667 = coord(2/3)
  0.5 = coord(1/2)
    Source
    Journal of the American Society for Information Science and Technology. 64(2013) no.10, S.2024-2044
  3. Kenter, T.; Balog, K.; Rijke, M. de: Evaluating document filtering systems over time (2015) 0.01 
    0.009324351 = product of:
  0.018648703 = sum of:
    0.018648703 = product of:
      0.027973052 = sum of:
        0.025598504 = weight(_text_:k in 2672) [ClassicSimilarity], result of:
          0.025598504 = score(doc=2672,freq=2.0), product of:
            0.16225883 = queryWeight, product of:
              3.569778 = idf(docFreq=3384, maxDocs=44218)
              0.04545348 = queryNorm
            0.15776339 = fieldWeight in 2672, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              3.569778 = idf(docFreq=3384, maxDocs=44218)
              0.03125 = fieldNorm(doc=2672)
        0.0023745487 = weight(_text_:s in 2672) [ClassicSimilarity], result of:
          0.0023745487 = score(doc=2672,freq=2.0), product of:
            0.049418733 = queryWeight, product of:
              1.0872376 = idf(docFreq=40523, maxDocs=44218)
              0.04545348 = queryNorm
            0.048049565 = fieldWeight in 2672, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              1.0872376 = idf(docFreq=40523, maxDocs=44218)
              0.03125 = fieldNorm(doc=2672)
      0.6666667 = coord(2/3)
  0.5 = coord(1/2)
    Source
    Information processing and management. 51(2015) no.6, S.791-808

Authors