-
Bishop, A.P.: Scholarly journals on the net : a reader's assessment (1995)
0.00
0.001203219 = product of:
0.002406438 = sum of:
0.002406438 = product of:
0.004812876 = sum of:
0.004812876 = weight(_text_:s in 2445) [ClassicSimilarity], result of:
0.004812876 = score(doc=2445,freq=2.0), product of:
0.05008241 = queryWeight, product of:
1.0872376 = idf(docFreq=40523, maxDocs=44218)
0.046063907 = queryNorm
0.09609913 = fieldWeight in 2445, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
1.0872376 = idf(docFreq=40523, maxDocs=44218)
0.0625 = fieldNorm(doc=2445)
0.5 = coord(1/2)
0.5 = coord(1/2)
- Source
- Library trends. 43(1995) no.4, S.544-570
-
Doty, P.; Bishop, A.P.: ¬The National Information Infrastructure and electronic publishing : a reflective essay (1994)
0.00
0.0010528166 = product of:
0.0021056333 = sum of:
0.0021056333 = product of:
0.0042112665 = sum of:
0.0042112665 = weight(_text_:s in 1058) [ClassicSimilarity], result of:
0.0042112665 = score(doc=1058,freq=2.0), product of:
0.05008241 = queryWeight, product of:
1.0872376 = idf(docFreq=40523, maxDocs=44218)
0.046063907 = queryNorm
0.08408674 = fieldWeight in 1058, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
1.0872376 = idf(docFreq=40523, maxDocs=44218)
0.0546875 = fieldNorm(doc=1058)
0.5 = coord(1/2)
0.5 = coord(1/2)
- Source
- Journal of the American Society for Information Science. 45(1994) no.10, S.785-799
-
Bishop, A.P.: ¬A pilot study of the Blacksburg Electronic village (1994)
0.00
0.0010528166 = product of:
0.0021056333 = sum of:
0.0021056333 = product of:
0.0042112665 = sum of:
0.0042112665 = weight(_text_:s in 3027) [ClassicSimilarity], result of:
0.0042112665 = score(doc=3027,freq=2.0), product of:
0.05008241 = queryWeight, product of:
1.0872376 = idf(docFreq=40523, maxDocs=44218)
0.046063907 = queryNorm
0.08408674 = fieldWeight in 3027, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
1.0872376 = idf(docFreq=40523, maxDocs=44218)
0.0546875 = fieldNorm(doc=3027)
0.5 = coord(1/2)
0.5 = coord(1/2)
- Pages
- S.18-42