Search (2 results, page 1 of 1)

Did you mean:
rvk_ss%3a%2000 73400 allgemeines %2f buch- und bibliothekswesen%2c informationswissenschaft %2f bibliothekswesen %2f bibliotheksbenutzung %2f auskunft%2c information%22 2
rvk_ss%3a%2200 73000 allgemeines %2f buch- und bibliothekswesen%2c informationswissenschaft %2f bibliothekswesen %2f bibliotheksbenutzung %2f auskunft%2c information%22 2
rvk_ss%3a%2200 73400 allgemeinen %2f buch- und bibliothekswesen%2c informationswissenschaft %2f bibliothekswesen %2f bibliotheksbenutzung %2f auskunft%2c information%22 2
rvk_ss%3a%2200 73400 allgemeines %2f buch- und bibliothekswesen%2c informationswissenschaft %2f bibliothekswesen %2f bibliotheksbenutzung %2f auskunfts%2c information%22 2
rvk_ss%3a%2200 73400 allgemeines %2f buch- und bibliothekswesen%2c informationswissenschaft %2f bibliothekswesen %2f bibliotheksbenutzung %2f auskünfte%2c information%22 2

Jansen, B.J.; Spink, A.; Blakely, C.; Koshman, S.: Defining a session on Web search engines (2007) 0.00

1.6844113E-4 = product of:
  0.0025266167 = sum of:
    0.0025266167 = product of:
      0.0050532334 = sum of:
        0.0050532334 = weight(_text_:information in 285) [ClassicSimilarity], result of:
          0.0050532334 = score(doc=285,freq=2.0), product of:
            0.052107345 = queryWeight, product of:
              1.7554779 = idf(docFreq=20772, maxDocs=44218)
              0.029682713 = queryNorm
            0.09697737 = fieldWeight in 285, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              1.7554779 = idf(docFreq=20772, maxDocs=44218)
              0.0390625 = fieldNorm(doc=285)
      0.5 = coord(1/2)
  0.06666667 = coord(1/15)

Source: Journal of the American Society for Information Science and Technology. 58(2007) no.6, S.862-871

Spink, A.; Jansen, B.J.; Blakely, C.; Koshman, S.: ¬A study of results overlap and uniqueness among major Web search engines (2006) 0.00

1.347529E-4 = product of:
  0.0020212934 = sum of:
    0.0020212934 = product of:
      0.004042587 = sum of:
        0.004042587 = weight(_text_:information in 993) [ClassicSimilarity], result of:
          0.004042587 = score(doc=993,freq=2.0), product of:
            0.052107345 = queryWeight, product of:
              1.7554779 = idf(docFreq=20772, maxDocs=44218)
              0.029682713 = queryNorm
            0.0775819 = fieldWeight in 993, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              1.7554779 = idf(docFreq=20772, maxDocs=44218)
              0.03125 = fieldNorm(doc=993)
      0.5 = coord(1/2)
  0.06666667 = coord(1/15)

Source: Information processing and management. 42(2006) no.5, S.1379-1391

Search (2 results, page 1 of 1)

Authors