-
Jones, S.; Gatford, M.; Robertson, S.; Hancock-Beaulieu, M.; Secker, J.; Walker, S.: Interactive thesaurus navigation : intelligence rules OK? (1995)
0.00
0.0021056333 = product of:
0.0042112665 = sum of:
0.0042112665 = product of:
0.008422533 = sum of:
0.008422533 = weight(_text_:s in 180) [ClassicSimilarity], result of:
0.008422533 = score(doc=180,freq=8.0), product of:
0.05008241 = queryWeight, product of:
1.0872376 = idf(docFreq=40523, maxDocs=44218)
0.046063907 = queryNorm
0.16817348 = fieldWeight in 180, product of:
2.828427 = tf(freq=8.0), with freq of:
8.0 = termFreq=8.0
1.0872376 = idf(docFreq=40523, maxDocs=44218)
0.0546875 = fieldNorm(doc=180)
0.5 = coord(1/2)
0.5 = coord(1/2)
- Source
- Journal of the American Society for Information Science. 46(1995) no.1, S.52-59
-
Jones, S.; Hancock-Beaulieu, M.: Support strategies for interactive thesaurus navigation (1994)
0.00
0.0014889077 = product of:
0.0029778155 = sum of:
0.0029778155 = product of:
0.005955631 = sum of:
0.005955631 = weight(_text_:s in 7734) [ClassicSimilarity], result of:
0.005955631 = score(doc=7734,freq=4.0), product of:
0.05008241 = queryWeight, product of:
1.0872376 = idf(docFreq=40523, maxDocs=44218)
0.046063907 = queryNorm
0.118916616 = fieldWeight in 7734, product of:
2.0 = tf(freq=4.0), with freq of:
4.0 = termFreq=4.0
1.0872376 = idf(docFreq=40523, maxDocs=44218)
0.0546875 = fieldNorm(doc=7734)
0.5 = coord(1/2)
0.5 = coord(1/2)
- Pages
- S.366-381
-
Jones, S.: ¬A thesaurus data model for an intelligent retrieval system (1993)
0.00
0.0012762066 = product of:
0.0025524131 = sum of:
0.0025524131 = product of:
0.0051048263 = sum of:
0.0051048263 = weight(_text_:s in 5279) [ClassicSimilarity], result of:
0.0051048263 = score(doc=5279,freq=4.0), product of:
0.05008241 = queryWeight, product of:
1.0872376 = idf(docFreq=40523, maxDocs=44218)
0.046063907 = queryNorm
0.101928525 = fieldWeight in 5279, product of:
2.0 = tf(freq=4.0), with freq of:
4.0 = termFreq=4.0
1.0872376 = idf(docFreq=40523, maxDocs=44218)
0.046875 = fieldNorm(doc=5279)
0.5 = coord(1/2)
0.5 = coord(1/2)
- Source
- Journal of information science. 19(1993), S.167-178