-
Kempf, A.O.; Zapilko, B.: Normdatenpflege in Zeiten der Automatisierung : Erstellung und Evaluation automatisch aufgebauter Thesaurus-Crosskonkordanzen (2013)
0.02
0.020435963 = product of:
0.040871926 = sum of:
0.040871926 = product of:
0.061307885 = sum of:
0.020527044 = weight(_text_:h in 1021) [ClassicSimilarity], result of:
0.020527044 = score(doc=1021,freq=2.0), product of:
0.124635 = queryWeight, product of:
2.4844491 = idf(docFreq=10020, maxDocs=44218)
0.05016605 = queryNorm
0.16469726 = fieldWeight in 1021, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
2.4844491 = idf(docFreq=10020, maxDocs=44218)
0.046875 = fieldNorm(doc=1021)
0.040780842 = weight(_text_:22 in 1021) [ClassicSimilarity], result of:
0.040780842 = score(doc=1021,freq=2.0), product of:
0.17567296 = queryWeight, product of:
3.5018296 = idf(docFreq=3622, maxDocs=44218)
0.05016605 = queryNorm
0.23214069 = fieldWeight in 1021, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.5018296 = idf(docFreq=3622, maxDocs=44218)
0.046875 = fieldNorm(doc=1021)
0.6666667 = coord(2/3)
0.5 = coord(1/2)
- Date
- 18. 8.2013 12:53:22
- Source
- Information - Wissenschaft und Praxis. 64(2013) H.4, S.199-208
-
Kempf, A.O.; Baum, K.: Von der Ein-Datenbank-Suche zum verteilten Suchszenario : Zum Aufbau von Crosskonkordanzen zwischen der Fachklassifikation Sozialwissenschaften und der Dewey-Dezimalklassifikation (2013)
0.01
0.011771888 = product of:
0.023543775 = sum of:
0.023543775 = product of:
0.070631325 = sum of:
0.070631325 = weight(_text_:k in 1654) [ClassicSimilarity], result of:
0.070631325 = score(doc=1654,freq=2.0), product of:
0.17908166 = queryWeight, product of:
3.569778 = idf(docFreq=3384, maxDocs=44218)
0.05016605 = queryNorm
0.39440846 = fieldWeight in 1654, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.569778 = idf(docFreq=3384, maxDocs=44218)
0.078125 = fieldNorm(doc=1654)
0.33333334 = coord(1/3)
0.5 = coord(1/2)
-
Kempf, A.O.; Ritze, D.; Eckert, K.; Zapilko, B.: New ways of mapping knowledge organization systems : using a semiautomatic matchingprocedure for building up vocabulary crosswalks (2013)
0.01
0.0070631327 = product of:
0.014126265 = sum of:
0.014126265 = product of:
0.042378794 = sum of:
0.042378794 = weight(_text_:k in 989) [ClassicSimilarity], result of:
0.042378794 = score(doc=989,freq=2.0), product of:
0.17908166 = queryWeight, product of:
3.569778 = idf(docFreq=3384, maxDocs=44218)
0.05016605 = queryNorm
0.23664509 = fieldWeight in 989, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.569778 = idf(docFreq=3384, maxDocs=44218)
0.046875 = fieldNorm(doc=989)
0.33333334 = coord(1/3)
0.5 = coord(1/2)
-
Kempf, A.O.; Ritze, D.; Eckert, K.; Zapilko, B.: New ways of mapping knowledge organization systems : using a semi-automatic matching procedure for building up vocabulary crosswalks (2014)
0.01
0.005885944 = product of:
0.011771888 = sum of:
0.011771888 = product of:
0.035315663 = sum of:
0.035315663 = weight(_text_:k in 1371) [ClassicSimilarity], result of:
0.035315663 = score(doc=1371,freq=2.0), product of:
0.17908166 = queryWeight, product of:
3.569778 = idf(docFreq=3384, maxDocs=44218)
0.05016605 = queryNorm
0.19720423 = fieldWeight in 1371, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.569778 = idf(docFreq=3384, maxDocs=44218)
0.0390625 = fieldNorm(doc=1371)
0.33333334 = coord(1/3)
0.5 = coord(1/2)
-
Kempf, A.O.: Thesauri und Interoperabilität mit anderen Vokabularen : Die neue Thesaurusnorm ISO 25964 (2013)
0.01
0.005701957 = product of:
0.011403914 = sum of:
0.011403914 = product of:
0.03421174 = sum of:
0.03421174 = weight(_text_:h in 1144) [ClassicSimilarity], result of:
0.03421174 = score(doc=1144,freq=2.0), product of:
0.124635 = queryWeight, product of:
2.4844491 = idf(docFreq=10020, maxDocs=44218)
0.05016605 = queryNorm
0.27449545 = fieldWeight in 1144, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
2.4844491 = idf(docFreq=10020, maxDocs=44218)
0.078125 = fieldNorm(doc=1144)
0.33333334 = coord(1/3)
0.5 = coord(1/2)
- Source
- Information - Wissenschaft und Praxis. 64(2013) H.6, S.365-368