Search (2 results, page 1 of 1)

Did you mean:
rswk_00%3a%22Google inc. %2f strategisches management%22 2
rswk_00%3a%22Google inc. %2f strategischen management%22 2
rswk_00%3a%22Google inc. %2f strategischer management%22 2
rswk_00%3a%22Google inc. %2f strategischem management%22 2
rswk_00%3a%22Google inc. %2f strategische management%22 2

Kishida, K.: Technical issues of cross-language information retrieval : a review (2005) 0.00

0.0042687347 = product of:
  0.021343673 = sum of:
    0.021343673 = product of:
      0.042687345 = sum of:
        0.042687345 = weight(_text_:management in 1019) [ClassicSimilarity], result of:
          0.042687345 = score(doc=1019,freq=2.0), product of:
            0.14328322 = queryWeight, product of:
              3.3706124 = idf(docFreq=4130, maxDocs=44218)
              0.042509552 = queryNorm
            0.29792285 = fieldWeight in 1019, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              3.3706124 = idf(docFreq=4130, maxDocs=44218)
              0.0625 = fieldNorm(doc=1019)
      0.5 = coord(1/2)
  0.2 = coord(1/5)

Source: Information processing and management. 41(2005) no.3, S.433-456

Kishida, K.: Term disambiguation techniques based on target document collection for cross-language information retrieval : an empirical comparison of performance between techniques (2007) 0.00

0.002667959 = product of:
  0.013339795 = sum of:
    0.013339795 = product of:
      0.02667959 = sum of:
        0.02667959 = weight(_text_:management in 897) [ClassicSimilarity], result of:
          0.02667959 = score(doc=897,freq=2.0), product of:
            0.14328322 = queryWeight, product of:
              3.3706124 = idf(docFreq=4130, maxDocs=44218)
              0.042509552 = queryNorm
            0.18620178 = fieldWeight in 897, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              3.3706124 = idf(docFreq=4130, maxDocs=44218)
              0.0390625 = fieldNorm(doc=897)
      0.5 = coord(1/2)
  0.2 = coord(1/5)

Source: Information processing and management. 43(2007) no.1, S.103-120