Search (2 results, page 1 of 1)
- Did you mean:
- author's%3a%22Ramdhian%2c S.%22 2
- authors%3a%22Ramdhian%2c S.%22 2
-
Lorenzen, M.: Using the Internet for reference service (1995)
0.00
0.001203219 = product of: 0.002406438 = sum of: 0.002406438 = product of: 0.004812876 = sum of: 0.004812876 = weight(_text_:s in 1088) [ClassicSimilarity], result of: 0.004812876 = score(doc=1088,freq=2.0), product of: 0.05008241 = queryWeight, product of: 1.0872376 = idf(docFreq=40523, maxDocs=44218) 0.046063907 = queryNorm 0.09609913 = fieldWeight in 1088, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 1.0872376 = idf(docFreq=40523, maxDocs=44218) 0.0625 = fieldNorm(doc=1088) 0.5 = coord(1/2) 0.5 = coord(1/2)
- Source
- Ohio libraries. 8(1995) no.3, S.23-24
-
Lorenzen, M.: Management by wandering around : reference rovering and quality reference service (1998)
0.00
0.001203219 = product of: 0.002406438 = sum of: 0.002406438 = product of: 0.004812876 = sum of: 0.004812876 = weight(_text_:s in 2196) [ClassicSimilarity], result of: 0.004812876 = score(doc=2196,freq=2.0), product of: 0.05008241 = queryWeight, product of: 1.0872376 = idf(docFreq=40523, maxDocs=44218) 0.046063907 = queryNorm 0.09609913 = fieldWeight in 2196, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 1.0872376 = idf(docFreq=40523, maxDocs=44218) 0.0625 = fieldNorm(doc=2196) 0.5 = coord(1/2) 0.5 = coord(1/2)
- Source
- Reference librarian. 1998, no.59, S.51-57