-
Miles, A.; Pérez-Agüera, J.R.: SKOS: Simple Knowledge Organisation for the Web (2006)
0.00
0.0013474762 = product of:
0.0026949523 = sum of:
0.0026949523 = product of:
0.008084857 = sum of:
0.008084857 = weight(_text_:e in 504) [ClassicSimilarity], result of:
0.008084857 = score(doc=504,freq=2.0), product of:
0.07272785 = queryWeight, product of:
1.43737 = idf(docFreq=28552, maxDocs=44218)
0.050597865 = queryNorm
0.1111659 = fieldWeight in 504, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
1.43737 = idf(docFreq=28552, maxDocs=44218)
0.0546875 = fieldNorm(doc=504)
0.33333334 = coord(1/3)
0.5 = coord(1/2)
- Language
- e
-
Miles, A.: SKOS: requirements for standardization (2006)
0.00
0.0011549797 = product of:
0.0023099594 = sum of:
0.0023099594 = product of:
0.0069298777 = sum of:
0.0069298777 = weight(_text_:e in 5703) [ClassicSimilarity], result of:
0.0069298777 = score(doc=5703,freq=2.0), product of:
0.07272785 = queryWeight, product of:
1.43737 = idf(docFreq=28552, maxDocs=44218)
0.050597865 = queryNorm
0.09528506 = fieldWeight in 5703, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
1.43737 = idf(docFreq=28552, maxDocs=44218)
0.046875 = fieldNorm(doc=5703)
0.33333334 = coord(1/3)
0.5 = coord(1/2)
- Language
- e
-
Assem, M. van; Malaisé, V.; Miles, A.; Schreiber, G.: ¬A method to convert thesauri to SKOS (2006)
0.00
0.0011549797 = product of:
0.0023099594 = sum of:
0.0023099594 = product of:
0.0069298777 = sum of:
0.0069298777 = weight(_text_:e in 4642) [ClassicSimilarity], result of:
0.0069298777 = score(doc=4642,freq=2.0), product of:
0.07272785 = queryWeight, product of:
1.43737 = idf(docFreq=28552, maxDocs=44218)
0.050597865 = queryNorm
0.09528506 = fieldWeight in 4642, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
1.43737 = idf(docFreq=28552, maxDocs=44218)
0.046875 = fieldNorm(doc=4642)
0.33333334 = coord(1/3)
0.5 = coord(1/2)
- Language
- e
-
Miles, A.; Matthews, B.; Beckett, D.; Brickley, D.; Wilson, M.; Rogers, N.: SKOS: A language to describe simple knowledge structures for the web (2005)
0.00
6.737381E-4 = product of:
0.0013474762 = sum of:
0.0013474762 = product of:
0.0040424285 = sum of:
0.0040424285 = weight(_text_:e in 517) [ClassicSimilarity], result of:
0.0040424285 = score(doc=517,freq=2.0), product of:
0.07272785 = queryWeight, product of:
1.43737 = idf(docFreq=28552, maxDocs=44218)
0.050597865 = queryNorm
0.05558295 = fieldWeight in 517, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
1.43737 = idf(docFreq=28552, maxDocs=44218)
0.02734375 = fieldNorm(doc=517)
0.33333334 = coord(1/3)
0.5 = coord(1/2)
- Language
- e