Search (2 results, page 1 of 1)
- Did you mean:
- author's%3a%22M%c3%böller%2c E.%22 2
- author's%3a%22M%c3%biller%2c E.%22 2
- authors%3a%22M%c3%böller%2c E.%22 2
- author's%3a%22M%c3%bilder%2c E.%22 2
- authors%3a%22M%c3%biller%2c E.%22 2
-
Nicholas, D.; Huntingdon, P.; Williams, P.: Evaluating digital platforms, services, channels and sites professionally (2003)
0.00
0.003010958 = product of: 0.006021916 = sum of: 0.006021916 = product of: 0.012043832 = sum of: 0.012043832 = weight(_text_:e in 5903) [ClassicSimilarity], result of: 0.012043832 = score(doc=5903,freq=2.0), product of: 0.05417053 = queryWeight, product of: 1.43737 = idf(docFreq=28552, maxDocs=44218) 0.037687257 = queryNorm 0.2223318 = fieldWeight in 5903, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 1.43737 = idf(docFreq=28552, maxDocs=44218) 0.109375 = fieldNorm(doc=5903) 0.5 = coord(1/2) 0.5 = coord(1/2)
- Language
- e
-
Nicholas, D.; Huntington, P.; Gunter, B.; Withey, R.; Russell, C.: ¬The British and their use of the Web for health information and advice : a survey (2003)
0.00
0.0012904105 = product of: 0.002580821 = sum of: 0.002580821 = product of: 0.005161642 = sum of: 0.005161642 = weight(_text_:e in 680) [ClassicSimilarity], result of: 0.005161642 = score(doc=680,freq=2.0), product of: 0.05417053 = queryWeight, product of: 1.43737 = idf(docFreq=28552, maxDocs=44218) 0.037687257 = queryNorm 0.09528506 = fieldWeight in 680, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 1.43737 = idf(docFreq=28552, maxDocs=44218) 0.046875 = fieldNorm(doc=680) 0.5 = coord(1/2) 0.5 = coord(1/2)
- Language
- e