Search (2 results, page 1 of 1)
- Did you mean:
- author's%3a%22R%c3%budin%2c P.%22 2
- author's%3a%22R%c3%bündig%2c P.%22 2
- authors%3a%22R%c3%budin%2c P.%22 2
- author's%3a%22R%c3%badia%2c P.%22 2
- authors%3a%22R%c3%bündig%2c P.%22 2
-
Nicholas, D.; Huntingdon, P.; Williams, P.: Evaluating digital platforms, services, channels and sites professionally (2003)
0.03
0.026441121 = product of: 0.052882243 = sum of: 0.052882243 = product of: 0.105764486 = sum of: 0.105764486 = weight(_text_:p in 5903) [ClassicSimilarity], result of: 0.105764486 = score(doc=5903,freq=4.0), product of: 0.13447173 = queryWeight, product of: 3.5955126 = idf(docFreq=3298, maxDocs=44218) 0.037399877 = queryNorm 0.7865184 = fieldWeight in 5903, product of: 2.0 = tf(freq=4.0), with freq of: 4.0 = termFreq=4.0 3.5955126 = idf(docFreq=3298, maxDocs=44218) 0.109375 = fieldNorm(doc=5903) 0.5 = coord(1/2) 0.5 = coord(1/2)
-
Nicholas, D.; Huntington, P.; Gunter, B.; Withey, R.; Russell, C.: ¬The British and their use of the Web for health information and advice : a survey (2003)
0.01
0.00801287 = product of: 0.01602574 = sum of: 0.01602574 = product of: 0.03205148 = sum of: 0.03205148 = weight(_text_:p in 680) [ClassicSimilarity], result of: 0.03205148 = score(doc=680,freq=2.0), product of: 0.13447173 = queryWeight, product of: 3.5955126 = idf(docFreq=3298, maxDocs=44218) 0.037399877 = queryNorm 0.23835106 = fieldWeight in 680, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 3.5955126 = idf(docFreq=3298, maxDocs=44218) 0.046875 = fieldNorm(doc=680) 0.5 = coord(1/2) 0.5 = coord(1/2)