Search (2 results, page 1 of 1)
- Did you mean:
- lcsh's%3a%22Cataloging %2f data processing%22 2
- lcshs%3a%22Cataloging %2f data processing%22 2
-
Salton, G.: ¬A simple blueprint for automatic Boolean query processing (1988)
0.02
0.02398075 = product of: 0.095923 = sum of: 0.095923 = product of: 0.191846 = sum of: 0.191846 = weight(_text_:processing in 6774) [ClassicSimilarity], result of: 0.191846 = score(doc=6774,freq=4.0), product of: 0.18956426 = queryWeight, product of: 4.048147 = idf(docFreq=2097, maxDocs=44218) 0.046827413 = queryNorm 1.0120368 = fieldWeight in 6774, product of: 2.0 = tf(freq=4.0), with freq of: 4.0 = termFreq=4.0 4.048147 = idf(docFreq=2097, maxDocs=44218) 0.125 = fieldNorm(doc=6774) 0.5 = coord(1/2) 0.25 = coord(1/4)
- Source
- Information processing and management. 24(1988) no.3, S.269-280
-
Salton, G.; Buckley, C.: Term-weighting approaches in automatic text retrieval (1988)
0.01
0.012717713 = product of: 0.05087085 = sum of: 0.05087085 = product of: 0.1017417 = sum of: 0.1017417 = weight(_text_:processing in 1938) [ClassicSimilarity], result of: 0.1017417 = score(doc=1938,freq=2.0), product of: 0.18956426 = queryWeight, product of: 4.048147 = idf(docFreq=2097, maxDocs=44218) 0.046827413 = queryNorm 0.53671354 = fieldWeight in 1938, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 4.048147 = idf(docFreq=2097, maxDocs=44218) 0.09375 = fieldNorm(doc=1938) 0.5 = coord(1/2) 0.25 = coord(1/4)
- Source
- Information processing and management. 24(1988) no.5, S.513-523