Search (2 results, page 1 of 1)
- Did you mean:
- rvk_ss%3a%2001 515 %28BVB%29%22 2
- rvk_ss%3a%2021 515 %28BVB%29%22 2
- rvk_ss%3a%2200 515 %28BVB%29%22 2
- rvk_ss%3a%2.01 515 %28BVB%29%22 2
- rvk_ss%3a%2202 515 %28BVB%29%22 2
-
Savic, D.: Designing an expert system for classifying office documents (1994)
0.01
0.005327759 = product of: 0.015983276 = sum of: 0.015983276 = product of: 0.04794983 = sum of: 0.04794983 = weight(_text_:29 in 2655) [ClassicSimilarity], result of: 0.04794983 = score(doc=2655,freq=2.0), product of: 0.15421791 = queryWeight, product of: 3.5176873 = idf(docFreq=3565, maxDocs=44218) 0.04384071 = queryNorm 0.31092256 = fieldWeight in 2655, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 3.5176873 = idf(docFreq=3565, maxDocs=44218) 0.0625 = fieldNorm(doc=2655) 0.33333334 = coord(1/3) 0.33333334 = coord(1/3)
- Source
- Records management quarterly. 28(1994) no.3, S.20-29
-
Savic, D.: Automatic classification of office documents : review of available methods and techniques (1995)
0.00
0.004661789 = product of: 0.0139853675 = sum of: 0.0139853675 = product of: 0.0419561 = sum of: 0.0419561 = weight(_text_:29 in 2219) [ClassicSimilarity], result of: 0.0419561 = score(doc=2219,freq=2.0), product of: 0.15421791 = queryWeight, product of: 3.5176873 = idf(docFreq=3565, maxDocs=44218) 0.04384071 = queryNorm 0.27205724 = fieldWeight in 2219, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 3.5176873 = idf(docFreq=3565, maxDocs=44218) 0.0546875 = fieldNorm(doc=2219) 0.33333334 = coord(1/3) 0.33333334 = coord(1/3)
- Source
- Records management quarterly. 29(1995) no.4, S.3-18