Search (2 results, page 1 of 1)

  • × author_ss:"Shafer, K.E."
  • × theme_ss:"Automatisches Klassifizieren"
  1. Subramanian, S.; Shafer, K.E.: Clustering (2001) 0.02
    0.01679651 = product of:
      0.10077906 = sum of:
        0.10077906 = sum of:
          0.03781292 = weight(_text_:4 in 1046) [ClassicSimilarity], result of:
            0.03781292 = score(doc=1046,freq=2.0), product of:
              0.105097495 = queryWeight, product of:
                2.7136984 = idf(docFreq=7967, maxDocs=44218)
                0.03872851 = queryNorm
              0.35978895 = fieldWeight in 1046, product of:
                1.4142135 = tf(freq=2.0), with freq of:
                  2.0 = termFreq=2.0
                2.7136984 = idf(docFreq=7967, maxDocs=44218)
                0.09375 = fieldNorm(doc=1046)
          0.06296614 = weight(_text_:22 in 1046) [ClassicSimilarity], result of:
            0.06296614 = score(doc=1046,freq=2.0), product of:
              0.13562064 = queryWeight, product of:
                3.5018296 = idf(docFreq=3622, maxDocs=44218)
                0.03872851 = queryNorm
              0.46428138 = fieldWeight in 1046, product of:
                1.4142135 = tf(freq=2.0), with freq of:
                  2.0 = termFreq=2.0
                3.5018296 = idf(docFreq=3622, maxDocs=44218)
                0.09375 = fieldNorm(doc=1046)
      0.16666667 = coord(1/6)
    
    Date
    5. 5.2003 14:17:22
    Source
    Journal of library administration. 34(2001) nos.3/4, S.221-228
  2. Shafer, K.E.: Evaluating Scorpion Results (2001) 0.00
    0.0026258973 = product of:
      0.015755383 = sum of:
        0.015755383 = product of:
          0.031510767 = sum of:
            0.031510767 = weight(_text_:4 in 4085) [ClassicSimilarity], result of:
              0.031510767 = score(doc=4085,freq=2.0), product of:
                0.105097495 = queryWeight, product of:
                  2.7136984 = idf(docFreq=7967, maxDocs=44218)
                  0.03872851 = queryNorm
                0.29982415 = fieldWeight in 4085, product of:
                  1.4142135 = tf(freq=2.0), with freq of:
                    2.0 = termFreq=2.0
                  2.7136984 = idf(docFreq=7967, maxDocs=44218)
                  0.078125 = fieldNorm(doc=4085)
          0.5 = coord(1/2)
      0.16666667 = coord(1/6)
    
    Source
    Journal of library administration. 34(2001) nos.3/4, S.237-244