Search (2 results, page 1 of 1)
- Did you mean:
- object's%3a%22INSPEC classification%22 2
- objects%3a%22INSPEC classification%22 2
-
Wellisch, H.H.: ¬A new classification of the world's languages (1982)
0.03
0.030356476 = product of: 0.060712952 = sum of: 0.060712952 = product of: 0.121425904 = sum of: 0.121425904 = weight(_text_:classification in 20) [ClassicSimilarity], result of: 0.121425904 = score(doc=20,freq=6.0), product of: 0.16603322 = queryWeight, product of: 3.1847067 = idf(docFreq=4974, maxDocs=44218) 0.05213454 = queryNorm 0.731335 = fieldWeight in 20, product of: 2.4494898 = tf(freq=6.0), with freq of: 6.0 = termFreq=6.0 3.1847067 = idf(docFreq=4974, maxDocs=44218) 0.09375 = fieldNorm(doc=20) 0.5 = coord(1/2) 0.5 = coord(1/2)
- Source
- Universal classification I: subject analysis and ordering systems. Proc. of the 4th Int. Study Conf. on Classification research, Augsburg, 28.6.-2.7.1982. Ed.: I. Dahlberg
-
Wellisch, H.H.: ¬The case of the missing subtitle (1981)
0.02
0.023368426 = product of: 0.04673685 = sum of: 0.04673685 = product of: 0.0934737 = sum of: 0.0934737 = weight(_text_:classification in 270) [ClassicSimilarity], result of: 0.0934737 = score(doc=270,freq=2.0), product of: 0.16603322 = queryWeight, product of: 3.1847067 = idf(docFreq=4974, maxDocs=44218) 0.05213454 = queryNorm 0.5629819 = fieldWeight in 270, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 3.1847067 = idf(docFreq=4974, maxDocs=44218) 0.125 = fieldNorm(doc=270) 0.5 = coord(1/2) 0.5 = coord(1/2)
- Source
- Cataloging and classification quarterly. 1(1981) no.1, S.73-76