-
Kempf, A.O.; Zapilko, B.: Normdatenpflege in Zeiten der Automatisierung : Erstellung und Evaluation automatisch aufgebauter Thesaurus-Crosskonkordanzen (2013)
0.03
0.027817883 = product of:
0.055635765 = sum of:
0.055635765 = sum of:
0.012652089 = weight(_text_:d in 1021) [ClassicSimilarity], result of:
0.012652089 = score(doc=1021,freq=2.0), product of:
0.10045733 = queryWeight, product of:
1.899872 = idf(docFreq=17979, maxDocs=44218)
0.052875843 = queryNorm
0.1259449 = fieldWeight in 1021, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
1.899872 = idf(docFreq=17979, maxDocs=44218)
0.046875 = fieldNorm(doc=1021)
0.042983677 = weight(_text_:22 in 1021) [ClassicSimilarity], result of:
0.042983677 = score(doc=1021,freq=2.0), product of:
0.18516219 = queryWeight, product of:
3.5018296 = idf(docFreq=3622, maxDocs=44218)
0.052875843 = queryNorm
0.23214069 = fieldWeight in 1021, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.5018296 = idf(docFreq=3622, maxDocs=44218)
0.046875 = fieldNorm(doc=1021)
0.5 = coord(1/2)
- Date
- 18. 8.2013 12:53:22
- Language
- d
-
Kempf, A.O.; Ritze, D.; Eckert, K.; Zapilko, B.: New ways of mapping knowledge organization systems : using a semiautomatic matchingprocedure for building up vocabulary crosswalks (2013)
0.00
0.0031630222 = product of:
0.0063260444 = sum of:
0.0063260444 = product of:
0.012652089 = sum of:
0.012652089 = weight(_text_:d in 989) [ClassicSimilarity], result of:
0.012652089 = score(doc=989,freq=2.0), product of:
0.10045733 = queryWeight, product of:
1.899872 = idf(docFreq=17979, maxDocs=44218)
0.052875843 = queryNorm
0.1259449 = fieldWeight in 989, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
1.899872 = idf(docFreq=17979, maxDocs=44218)
0.046875 = fieldNorm(doc=989)
0.5 = coord(1/2)
0.5 = coord(1/2)
-
Kempf, A.O.; Ritze, D.; Eckert, K.; Zapilko, B.: New ways of mapping knowledge organization systems : using a semi-automatic matching procedure for building up vocabulary crosswalks (2014)
0.00
0.002635852 = product of:
0.005271704 = sum of:
0.005271704 = product of:
0.010543408 = sum of:
0.010543408 = weight(_text_:d in 1371) [ClassicSimilarity], result of:
0.010543408 = score(doc=1371,freq=2.0), product of:
0.10045733 = queryWeight, product of:
1.899872 = idf(docFreq=17979, maxDocs=44218)
0.052875843 = queryNorm
0.104954086 = fieldWeight in 1371, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
1.899872 = idf(docFreq=17979, maxDocs=44218)
0.0390625 = fieldNorm(doc=1371)
0.5 = coord(1/2)
0.5 = coord(1/2)