Search (2 results, page 1 of 1)
- Did you mean:
- object's%3a%22Engineering index classification%22 2
- objects%3a%22Engineering index classification%22 2
-
Keyser, P. de: Indexing : from thesauri to the Semantic Web (2012)
0.01
0.0068870517 = product of: 0.020661155 = sum of: 0.020661155 = product of: 0.04132231 = sum of: 0.04132231 = weight(_text_:22 in 3197) [ClassicSimilarity], result of: 0.04132231 = score(doc=3197,freq=2.0), product of: 0.17800546 = queryWeight, product of: 3.5018296 = idf(docFreq=3622, maxDocs=44218) 0.05083213 = queryNorm 0.23214069 = fieldWeight in 3197, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 3.5018296 = idf(docFreq=3622, maxDocs=44218) 0.046875 = fieldNorm(doc=3197) 0.5 = coord(1/2) 0.33333334 = coord(1/3)
- Date
- 24. 8.2016 14:03:22
-
Lubas, R.L.; Jackson, A.S.; Schneider, I.: ¬The metadata manual : a practical workbook (2013)
0.01
0.0056961607 = product of: 0.017088482 = sum of: 0.017088482 = product of: 0.034176964 = sum of: 0.034176964 = weight(_text_:classification in 2089) [ClassicSimilarity], result of: 0.034176964 = score(doc=2089,freq=2.0), product of: 0.16188543 = queryWeight, product of: 3.1847067 = idf(docFreq=4974, maxDocs=44218) 0.05083213 = queryNorm 0.21111822 = fieldWeight in 2089, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 3.1847067 = idf(docFreq=4974, maxDocs=44218) 0.046875 = fieldNorm(doc=2089) 0.5 = coord(1/2) 0.33333334 = coord(1/3)
- Footnote
- Volltext unter: http://lib.myilibrary.com/Open.aspx?id=548935. Rez. in: Cataloging and classification quarterly 52(2015) no.2, S.250-251 (Timothy Keller).
Authors
Subjects
Classifications
- 005.74 1
- 025.3 1
- 06.54 (Bibliotheksautomatisierung) 1
- 06.74 (Informationssysteme) 1
- 54.72 (Künstliche Intelligenz) 1
- AN 9255 1
- AN 95000 1
- AN 95100 1
- QA76.9 1
- More… Less…