Search (3 results, page 1 of 1)

  • × language_ss:"chi"
  • × theme_ss:"Metadaten"
  1. Wu, C.-J.: Mapping the Dublin Core to the Chinese MARC (1998) 0.02
    0.015175708 = product of:
      0.06070283 = sum of:
        0.06070283 = weight(_text_:c in 6269) [ClassicSimilarity], result of:
          0.06070283 = score(doc=6269,freq=2.0), product of:
            0.15927945 = queryWeight, product of:
              3.4494052 = idf(docFreq=3817, maxDocs=44218)
              0.046175916 = queryNorm
            0.381109 = fieldWeight in 6269, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              3.4494052 = idf(docFreq=3817, maxDocs=44218)
              0.078125 = fieldNorm(doc=6269)
      0.25 = coord(1/4)
    
  2. Wu, C.-J.: Metadata and future developments in cataloguing (1997) 0.01
    0.010622995 = product of:
      0.04249198 = sum of:
        0.04249198 = weight(_text_:c in 2826) [ClassicSimilarity], result of:
          0.04249198 = score(doc=2826,freq=2.0), product of:
            0.15927945 = queryWeight, product of:
              3.4494052 = idf(docFreq=3817, maxDocs=44218)
              0.046175916 = queryNorm
            0.2667763 = fieldWeight in 2826, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              3.4494052 = idf(docFreq=3817, maxDocs=44218)
              0.0546875 = fieldNorm(doc=2826)
      0.25 = coord(1/4)
    
  3. Wu, C.-J.: Experiments on using the Dublin Core to reduce the retrieval error ratio (1998) 0.01
    0.010622995 = product of:
      0.04249198 = sum of:
        0.04249198 = weight(_text_:c in 5201) [ClassicSimilarity], result of:
          0.04249198 = score(doc=5201,freq=2.0), product of:
            0.15927945 = queryWeight, product of:
              3.4494052 = idf(docFreq=3817, maxDocs=44218)
              0.046175916 = queryNorm
            0.2667763 = fieldWeight in 5201, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              3.4494052 = idf(docFreq=3817, maxDocs=44218)
              0.0546875 = fieldNorm(doc=5201)
      0.25 = coord(1/4)