-
Magennis, M.: Expert rule-based query expansion (1995)
0.00
2.3911135E-4 = product of:
0.005499561 = sum of:
0.005499561 = product of:
0.010999122 = sum of:
0.010999122 = weight(_text_:1 in 5181) [ClassicSimilarity], result of:
0.010999122 = score(doc=5181,freq=2.0), product of:
0.057894554 = queryWeight, product of:
2.4565027 = idf(docFreq=10304, maxDocs=44218)
0.023567878 = queryNorm
0.18998542 = fieldWeight in 5181, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
2.4565027 = idf(docFreq=10304, maxDocs=44218)
0.0546875 = fieldNorm(doc=5181)
0.5 = coord(1/2)
0.04347826 = coord(1/23)
- Source
- New review of document and text management. 1995, no.1, S.63-83
-
Colace, F.; Santo, M. De; Greco, L.; Napoletano, P.: Weighted word pairs for query expansion (2015)
0.00
2.3911135E-4 = product of:
0.005499561 = sum of:
0.005499561 = product of:
0.010999122 = sum of:
0.010999122 = weight(_text_:1 in 2687) [ClassicSimilarity], result of:
0.010999122 = score(doc=2687,freq=2.0), product of:
0.057894554 = queryWeight, product of:
2.4565027 = idf(docFreq=10304, maxDocs=44218)
0.023567878 = queryNorm
0.18998542 = fieldWeight in 2687, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
2.4565027 = idf(docFreq=10304, maxDocs=44218)
0.0546875 = fieldNorm(doc=2687)
0.5 = coord(1/2)
0.04347826 = coord(1/23)
- Source
- Information processing and management. 51(2015) no.1, S.179-193
-
Li, N.; Sun, J.: Improving Chinese term association from the linguistic perspective (2017)
0.00
2.0495258E-4 = product of:
0.0047139092 = sum of:
0.0047139092 = product of:
0.0094278185 = sum of:
0.0094278185 = weight(_text_:1 in 3381) [ClassicSimilarity], result of:
0.0094278185 = score(doc=3381,freq=2.0), product of:
0.057894554 = queryWeight, product of:
2.4565027 = idf(docFreq=10304, maxDocs=44218)
0.023567878 = queryNorm
0.16284466 = fieldWeight in 3381, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
2.4565027 = idf(docFreq=10304, maxDocs=44218)
0.046875 = fieldNorm(doc=3381)
0.5 = coord(1/2)
0.04347826 = coord(1/23)
- Source
- Knowledge organization. 44(2017) no.1, S.13-23