Search (2 results, page 1 of 1)
- Did you mean:
- rswk_00%3a%22Gehirnforschung %2f lernen %28%c3%9612%29%22 2
- rswk_00%3a%22Gehirnforschung %2f lernens %28%c3%9617%29%22 2
- rswk_00%3a%22Gehirnforschung %2f learners %28%c3%9612%29%22 2
- rswk_00%3a%22Gehirnforschung %2f lernen %28%c3%9617%29%22 2
- rswk_00%3a%22Gehirnforschung %2f lernens %28%c3%9632%29%22 2
-
Jantz, R.C.: ¬An approach to managing vocabulary for databases on the Web (1999)
0.00
0.0021622765 = product of: 0.008649106 = sum of: 0.008649106 = product of: 0.043245528 = sum of: 0.043245528 = weight(_text_:28 in 5354) [ClassicSimilarity], result of: 0.043245528 = score(doc=5354,freq=2.0), product of: 0.1365805 = queryWeight, product of: 3.5822632 = idf(docFreq=3342, maxDocs=44218) 0.038126875 = queryNorm 0.31663033 = fieldWeight in 5354, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 3.5822632 = idf(docFreq=3342, maxDocs=44218) 0.0625 = fieldNorm(doc=5354) 0.2 = coord(1/5) 0.25 = coord(1/4)
- Source
- Cataloging and classification quarterly. 28(1999) no.3, S.55-65
-
Russell, B.M.; Spillane, J.L.: Using the Web for name authority work (2001)
0.00
0.0018079829 = product of: 0.0072319317 = sum of: 0.0072319317 = product of: 0.036159657 = sum of: 0.036159657 = weight(_text_:22 in 167) [ClassicSimilarity], result of: 0.036159657 = score(doc=167,freq=2.0), product of: 0.13351382 = queryWeight, product of: 3.5018296 = idf(docFreq=3622, maxDocs=44218) 0.038126875 = queryNorm 0.2708308 = fieldWeight in 167, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 3.5018296 = idf(docFreq=3622, maxDocs=44218) 0.0546875 = fieldNorm(doc=167) 0.2 = coord(1/5) 0.25 = coord(1/4)
- Date
- 10. 9.2000 17:38:22