Search (2 results, page 1 of 1)

  • × theme_ss:"Automatisches Indexieren"
  • × theme_ss:"Konzeption und Anwendung des Prinzips Thesaurus"
  1. Siebenkäs, A.; Markscheffel, B.: Conception of a workflow for the semi-automatic construction of a thesaurus for the German printing industry (2015) 0.02
    0.015969815 = product of:
      0.03193963 = sum of:
        0.03193963 = product of:
          0.06387926 = sum of:
            0.06387926 = weight(_text_:f in 2091) [ClassicSimilarity], result of:
              0.06387926 = score(doc=2091,freq=2.0), product of:
                0.20722532 = queryWeight, product of:
                  3.985786 = idf(docFreq=2232, maxDocs=44218)
                  0.051991083 = queryNorm
                0.3082599 = fieldWeight in 2091, product of:
                  1.4142135 = tf(freq=2.0), with freq of:
                    2.0 = termFreq=2.0
                  3.985786 = idf(docFreq=2232, maxDocs=44218)
                  0.0546875 = fieldNorm(doc=2091)
          0.5 = coord(1/2)
      0.5 = coord(1/2)
    
    Source
    Re:inventing information science in the networked society: Proceedings of the 14th International Symposium on Information Science, Zadar/Croatia, 19th-21st May 2015. Eds.: F. Pehar, C. Schloegl u. C. Wolff
  2. Milstead, J.L.: Thesauri in a full-text world (1998) 0.01
    0.008805092 = product of:
      0.017610185 = sum of:
        0.017610185 = product of:
          0.03522037 = sum of:
            0.03522037 = weight(_text_:22 in 2337) [ClassicSimilarity], result of:
              0.03522037 = score(doc=2337,freq=2.0), product of:
                0.1820639 = queryWeight, product of:
                  3.5018296 = idf(docFreq=3622, maxDocs=44218)
                  0.051991083 = queryNorm
                0.19345059 = fieldWeight in 2337, product of:
                  1.4142135 = tf(freq=2.0), with freq of:
                    2.0 = termFreq=2.0
                  3.5018296 = idf(docFreq=3622, maxDocs=44218)
                  0.0390625 = fieldNorm(doc=2337)
          0.5 = coord(1/2)
      0.5 = coord(1/2)
    
    Date
    22. 9.1997 19:16:05