Search (2 results, page 1 of 1)
- Did you mean:
- author's%3a%22Nuotio%2c S.%22 2
- authors%3a%22Nuotio%2c S.%22 2
-
Keitz, W. von: Automatic indexing and the dissemination of information (1986)
0.00
0.002406438 = product of: 0.004812876 = sum of: 0.004812876 = product of: 0.009625752 = sum of: 0.009625752 = weight(_text_:s in 2390) [ClassicSimilarity], result of: 0.009625752 = score(doc=2390,freq=2.0), product of: 0.05008241 = queryWeight, product of: 1.0872376 = idf(docFreq=40523, maxDocs=44218) 0.046063907 = queryNorm 0.19219826 = fieldWeight in 2390, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 1.0872376 = idf(docFreq=40523, maxDocs=44218) 0.125 = fieldNorm(doc=2390) 0.5 = coord(1/2) 0.5 = coord(1/2)
- Source
- Inspel. 20(1986) no.1, S.47-67
-
O'Kane, K.C.: Generating hierarchical document indices from common denominators in large document collections (1996)
0.00
0.0010528166 = product of: 0.0021056333 = sum of: 0.0021056333 = product of: 0.0042112665 = sum of: 0.0042112665 = weight(_text_:s in 4037) [ClassicSimilarity], result of: 0.0042112665 = score(doc=4037,freq=2.0), product of: 0.05008241 = queryWeight, product of: 1.0872376 = idf(docFreq=40523, maxDocs=44218) 0.046063907 = queryNorm 0.08408674 = fieldWeight in 4037, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 1.0872376 = idf(docFreq=40523, maxDocs=44218) 0.0546875 = fieldNorm(doc=4037) 0.5 = coord(1/2) 0.5 = coord(1/2)
- Source
- Information processing and management. 32(1996) no.2, S.105-115