-
Tergan, S.-O.: Zum Aufbau von Wissensstrukturen mit Texten und Hypertexten (1993)
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- Source
- Nachrichten für Dokumentation. 44(1993) H.1, S.15-22
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Wingert, B.: Äußerer und innerer Hypertext : eine notwendige Differenzierung, verdeutlicht am Flusser-Hypertext (1993)
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- Source
- Nachrichten für Dokumentation. 44(1993) H.1, S.29-36
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Kircz, J.G.: Modularity : the next form of scientific information presentation? (1998)
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- Date
- 2.12.2005 14:29:55