-
Pejtersen, A.M.: Implications of users' value perception for the design of a bibliographic retrieval system (1986)
0.00
0.0011852094 = product of:
0.009481675 = sum of:
0.009481675 = product of:
0.047408372 = sum of:
0.047408372 = weight(_text_:29 in 2961) [ClassicSimilarity], result of:
0.047408372 = score(doc=2961,freq=2.0), product of:
0.101650976 = queryWeight, product of:
3.5176873 = idf(docFreq=3565, maxDocs=44218)
0.028897103 = queryNorm
0.46638384 = fieldWeight in 2961, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.5176873 = idf(docFreq=3565, maxDocs=44218)
0.09375 = fieldNorm(doc=2961)
0.2 = coord(1/5)
0.125 = coord(1/8)
- Date
- 5. 8.2006 10:16:29
-
Jäger-Dengler-Harles, I.: Informationsvisualisierung und Retrieval im Fokus der Infromationspraxis (2013)
0.00
5.872738E-4 = product of:
0.0046981904 = sum of:
0.0046981904 = product of:
0.02349095 = sum of:
0.02349095 = weight(_text_:22 in 1709) [ClassicSimilarity], result of:
0.02349095 = score(doc=1709,freq=2.0), product of:
0.10119273 = queryWeight, product of:
3.5018296 = idf(docFreq=3622, maxDocs=44218)
0.028897103 = queryNorm
0.23214069 = fieldWeight in 1709, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.5018296 = idf(docFreq=3622, maxDocs=44218)
0.046875 = fieldNorm(doc=1709)
0.2 = coord(1/5)
0.125 = coord(1/8)
- Date
- 4. 2.2015 9:22:39
-
Seeliger, F.: ¬A tool for systematic visualization of controlled descriptors and their relation to others as a rich context for a discovery system (2015)
0.00
4.097079E-4 = product of:
0.0032776631 = sum of:
0.0032776631 = product of:
0.016388316 = sum of:
0.016388316 = weight(_text_:28 in 2547) [ClassicSimilarity], result of:
0.016388316 = score(doc=2547,freq=2.0), product of:
0.103517026 = queryWeight, product of:
3.5822632 = idf(docFreq=3342, maxDocs=44218)
0.028897103 = queryNorm
0.15831517 = fieldWeight in 2547, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.5822632 = idf(docFreq=3342, maxDocs=44218)
0.03125 = fieldNorm(doc=2547)
0.2 = coord(1/5)
0.125 = coord(1/8)
- Date
- 14. 1.2016 18:09:28