-
Rösener, C.: ¬Die Stecknadel im Heuhaufen : Natürlichsprachlicher Zugang zu Volltextdatenbanken (2005)
0.01
0.0050912094 = product of:
0.020364838 = sum of:
0.0145765 = product of:
0.058306 = sum of:
0.058306 = weight(_text_:recherche in 548) [ClassicSimilarity], result of:
0.058306 = score(doc=548,freq=4.0), product of:
0.1721133 = queryWeight, product of:
5.4202437 = idf(docFreq=531, maxDocs=44218)
0.031753793 = queryNorm
0.33876523 = fieldWeight in 548, product of:
2.0 = tf(freq=4.0), with freq of:
4.0 = termFreq=4.0
5.4202437 = idf(docFreq=531, maxDocs=44218)
0.03125 = fieldNorm(doc=548)
0.25 = coord(1/4)
0.0057883374 = product of:
0.017365012 = sum of:
0.017365012 = weight(_text_:29 in 548) [ClassicSimilarity], result of:
0.017365012 = score(doc=548,freq=2.0), product of:
0.11169992 = queryWeight, product of:
3.5176873 = idf(docFreq=3565, maxDocs=44218)
0.031753793 = queryNorm
0.15546128 = fieldWeight in 548, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.5176873 = idf(docFreq=3565, maxDocs=44218)
0.03125 = fieldNorm(doc=548)
0.33333334 = coord(1/3)
0.25 = coord(2/8)
- Date
- 29. 3.2009 11:11:45
- RSWK
- Brockhaus-Enzyklopädie / Multimedia / Recherche
- Subject
- Brockhaus-Enzyklopädie / Multimedia / Recherche
-
Voorhees, E.M.: Question answering in TREC (2005)
0.00
0.0021706265 = product of:
0.017365012 = sum of:
0.017365012 = product of:
0.052095037 = sum of:
0.052095037 = weight(_text_:29 in 6487) [ClassicSimilarity], result of:
0.052095037 = score(doc=6487,freq=2.0), product of:
0.11169992 = queryWeight, product of:
3.5176873 = idf(docFreq=3565, maxDocs=44218)
0.031753793 = queryNorm
0.46638384 = fieldWeight in 6487, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.5176873 = idf(docFreq=3565, maxDocs=44218)
0.09375 = fieldNorm(doc=6487)
0.33333334 = coord(1/3)
0.125 = coord(1/8)
- Date
- 29. 3.1996 18:16:49
-
Ferret, O.; Grau, B.; Hurault-Plantet, M.; Illouz, G.; Jacquemin, C.; Monceaux, L.; Robba, I.; Vilnat, A.: How NLP can improve question answering (2002)
0.00
0.0010853133 = product of:
0.008682506 = sum of:
0.008682506 = product of:
0.026047518 = sum of:
0.026047518 = weight(_text_:29 in 1850) [ClassicSimilarity], result of:
0.026047518 = score(doc=1850,freq=2.0), product of:
0.11169992 = queryWeight, product of:
3.5176873 = idf(docFreq=3565, maxDocs=44218)
0.031753793 = queryNorm
0.23319192 = fieldWeight in 1850, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.5176873 = idf(docFreq=3565, maxDocs=44218)
0.046875 = fieldNorm(doc=1850)
0.33333334 = coord(1/3)
0.125 = coord(1/8)
- Source
- Knowledge organization. 29(2002) nos.3/4, S.135-155