Search (2 results, page 1 of 1)
- Did you mean:
- rswk_00%3a%22Internet %2f suchmaschinen %2f wegweiser %28%c3%9000%29%22 2
- rswk_00%3a%22Internet %2f suchmaschinen %2f wegweisers %28%c3%9600%29%22 2
- rswk_00%3a%22Internet %2f suchmaschinen %2f wegweise %28%c3%9600%29%22 2
- rswk_00%3a%22Internet %2f suchmaschinen %2f wegweiser %28%c3%96000%29%22 2
- rswk_00%3a%22Internet %2f suchmaschinen %2f wegweisers %28%c3%9000%29%22 2
-
Root thesaurus. Pt.1.2 (1985)
0.00
0.0019146665 = product of: 0.011487999 = sum of: 0.011487999 = product of: 0.057439994 = sum of: 0.057439994 = weight(_text_:22 in 467) [ClassicSimilarity], result of: 0.057439994 = score(doc=467,freq=2.0), product of: 0.12371807 = queryWeight, product of: 3.5018296 = idf(docFreq=3622, maxDocs=44218) 0.03532955 = queryNorm 0.46428138 = fieldWeight in 467, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 3.5018296 = idf(docFreq=3622, maxDocs=44218) 0.09375 = fieldNorm(doc=467) 0.2 = coord(1/5) 0.16666667 = coord(1/6)
- Date
- 18. 5.2007 14:22:43
-
Zeng, L.: ¬An introduction to thesauri and classification systems in the People's Republic of China (1986)
0.00
0.0013357553 = product of: 0.008014532 = sum of: 0.008014532 = product of: 0.040072657 = sum of: 0.040072657 = weight(_text_:28 in 1731) [ClassicSimilarity], result of: 0.040072657 = score(doc=1731,freq=2.0), product of: 0.12655975 = queryWeight, product of: 3.5822632 = idf(docFreq=3342, maxDocs=44218) 0.03532955 = queryNorm 0.31663033 = fieldWeight in 1731, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 3.5822632 = idf(docFreq=3342, maxDocs=44218) 0.0625 = fieldNorm(doc=1731) 0.2 = coord(1/5) 0.16666667 = coord(1/6)
- Source
- International classification. 13(1986), S.24-28