-
Stöber, T.: Serviceangebote der wissenschaftlichen Bibliotheken im Bereich Literaturverwaltung : Ergebnisse einer Umfrage (2010)
0.02
0.017277118 = product of:
0.034554236 = sum of:
0.034554236 = product of:
0.06910847 = sum of:
0.06910847 = weight(_text_:t in 3722) [ClassicSimilarity], result of:
0.06910847 = score(doc=3722,freq=2.0), product of:
0.19847474 = queryWeight, product of:
3.9394085 = idf(docFreq=2338, maxDocs=44218)
0.05038186 = queryNorm
0.34819782 = fieldWeight in 3722, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.9394085 = idf(docFreq=2338, maxDocs=44218)
0.0625 = fieldNorm(doc=3722)
0.5 = coord(1/2)
0.5 = coord(1/2)
-
Drewer, P.; Massion, F; Pulitano, D: Was haben Wissensmodellierung, Wissensstrukturierung, künstliche Intelligenz und Terminologie miteinander zu tun? (2017)
0.02
0.017065117 = product of:
0.034130234 = sum of:
0.034130234 = product of:
0.06826047 = sum of:
0.06826047 = weight(_text_:22 in 5576) [ClassicSimilarity], result of:
0.06826047 = score(doc=5576,freq=2.0), product of:
0.17642869 = queryWeight, product of:
3.5018296 = idf(docFreq=3622, maxDocs=44218)
0.05038186 = queryNorm
0.38690117 = fieldWeight in 5576, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.5018296 = idf(docFreq=3622, maxDocs=44218)
0.078125 = fieldNorm(doc=5576)
0.5 = coord(1/2)
0.5 = coord(1/2)
- Date
- 13.12.2017 14:17:22
-
Förderung von Informationsinfrastrukturen für die Wissenschaft : Ein Positionspapier der Deutschen Forschungsgemeinschaft (2018)
0.01
0.008532559 = product of:
0.017065117 = sum of:
0.017065117 = product of:
0.034130234 = sum of:
0.034130234 = weight(_text_:22 in 4178) [ClassicSimilarity], result of:
0.034130234 = score(doc=4178,freq=2.0), product of:
0.17642869 = queryWeight, product of:
3.5018296 = idf(docFreq=3622, maxDocs=44218)
0.05038186 = queryNorm
0.19345059 = fieldWeight in 4178, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.5018296 = idf(docFreq=3622, maxDocs=44218)
0.0390625 = fieldNorm(doc=4178)
0.5 = coord(1/2)
0.5 = coord(1/2)
- Date
- 22. 3.2018 17:30:43