Boden, H.: Bibliographische Ermittlungsaufgaben : Gruppenaufgaben 01-35 (1980)
0.01
0.010644181 = product of:
0.03725463 = sum of:
0.0075100823 = product of:
0.03004033 = sum of:
0.03004033 = weight(_text_:m in 3679) [ClassicSimilarity], result of:
0.03004033 = score(doc=3679,freq=2.0), product of:
0.06828904 = queryWeight, product of:
2.4884486 = idf(docFreq=9980, maxDocs=44218)
0.027442416 = queryNorm
0.4398997 = fieldWeight in 3679, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
2.4884486 = idf(docFreq=9980, maxDocs=44218)
0.125 = fieldNorm(doc=3679)
0.25 = coord(1/4)
0.029744549 = product of:
0.059489097 = sum of:
0.059489097 = weight(_text_:22 in 3679) [ClassicSimilarity], result of:
0.059489097 = score(doc=3679,freq=2.0), product of:
0.09609867 = queryWeight, product of:
3.5018296 = idf(docFreq=3622, maxDocs=44218)
0.027442416 = queryNorm
0.61904186 = fieldWeight in 3679, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.5018296 = idf(docFreq=3622, maxDocs=44218)
0.125 = fieldNorm(doc=3679)
0.5 = coord(1/2)
0.2857143 = coord(2/7)
- Date
- 22. 5.1999 18:14:05
- Type
- m
Canonne, A.: Vocabulaire élémentaire des classifications (1993)
0.01
0.0071141766 = product of:
0.024899617 = sum of:
0.005632562 = product of:
0.022530248 = sum of:
0.022530248 = weight(_text_:m in 2014) [ClassicSimilarity], result of:
0.022530248 = score(doc=2014,freq=2.0), product of:
0.06828904 = queryWeight, product of:
2.4884486 = idf(docFreq=9980, maxDocs=44218)
0.027442416 = queryNorm
0.3299248 = fieldWeight in 2014, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
2.4884486 = idf(docFreq=9980, maxDocs=44218)
0.09375 = fieldNorm(doc=2014)
0.25 = coord(1/4)
0.019267054 = product of:
0.05780116 = sum of:
0.05780116 = weight(_text_:f in 2014) [ClassicSimilarity], result of:
0.05780116 = score(doc=2014,freq=2.0), product of:
0.1093796 = queryWeight, product of:
3.985786 = idf(docFreq=2232, maxDocs=44218)
0.027442416 = queryNorm
0.52844554 = fieldWeight in 2014, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.985786 = idf(docFreq=2232, maxDocs=44218)
0.09375 = fieldNorm(doc=2014)
0.33333334 = coord(1/3)
0.2857143 = coord(2/7)
- Language
- f
- Type
- m
