Search (2 results, page 1 of 1)

  • × author_ss:"Lee, D.L."
  • × theme_ss:"Retrievalalgorithmen"
  1. Couvreur, T.R.; Benzel, R.N.; Miller, S.F.; Zeitler, D.N.; Lee, D.L.; Singhal, M.; Shivaratri, N.; Wong, W.Y.P.: ¬An analysis of performance and cost factors in searching large text databases using parallel search systems (1994) 0.01
    0.010729606 = product of:
      0.021459213 = sum of:
        0.021459213 = product of:
          0.064377636 = sum of:
            0.064377636 = weight(_text_:n in 7657) [ClassicSimilarity], result of:
              0.064377636 = score(doc=7657,freq=2.0), product of:
                0.19305801 = queryWeight, product of:
                  4.3116565 = idf(docFreq=1611, maxDocs=44218)
                  0.044775832 = queryNorm
                0.33346266 = fieldWeight in 7657, product of:
                  1.4142135 = tf(freq=2.0), with freq of:
                    2.0 = termFreq=2.0
                  4.3116565 = idf(docFreq=1611, maxDocs=44218)
                  0.0546875 = fieldNorm(doc=7657)
          0.33333334 = coord(1/3)
      0.5 = coord(1/2)
    
  2. Dang, E.K.F.; Luk, R.W.P.; Allan, J.; Ho, K.S.; Chung, K.F.L.; Lee, D.L.: ¬A new context-dependent term weight computed by boost and discount using relevance information (2010) 0.00
    0.0041623404 = product of:
      0.008324681 = sum of:
        0.008324681 = product of:
          0.024974043 = sum of:
            0.024974043 = weight(_text_:j in 4120) [ClassicSimilarity], result of:
              0.024974043 = score(doc=4120,freq=2.0), product of:
                0.14227505 = queryWeight, product of:
                  3.1774964 = idf(docFreq=5010, maxDocs=44218)
                  0.044775832 = queryNorm
                0.17553353 = fieldWeight in 4120, product of:
                  1.4142135 = tf(freq=2.0), with freq of:
                    2.0 = termFreq=2.0
                  3.1774964 = idf(docFreq=5010, maxDocs=44218)
                  0.0390625 = fieldNorm(doc=4120)
          0.33333334 = coord(1/3)
      0.5 = coord(1/2)