Search (2 results, page 1 of 1)

Did you mean:
author's%3a%22Oehlschl%c3%anger%2c S.%22 2
author's%3a%22Oehlschl%c3%alger%2c S.%22 2
authors%3a%22Oehlschl%c3%anger%2c S.%22 2
author's%3a%22Oehlschl%c3%arger%2c S.%22 2
authors%3a%22Oehlschl%c3%alger%2c S.%22 2

Moura, E.S. de; Fernandes, D.; Ribeiro-Neto, B.; Silva, A.S. da; Gonçalves, M.A.: Using structural information to improve search in Web collections (2010) 0.00

7.387756E-4 = product of:
  0.0014775512 = sum of:
    0.0014775512 = product of:
      0.0029551024 = sum of:
        0.0029551024 = weight(_text_:s in 4119) [ClassicSimilarity], result of:
          0.0029551024 = score(doc=4119,freq=2.0), product of:
            0.04100075 = queryWeight, product of:
              1.0872376 = idf(docFreq=40523, maxDocs=44218)
              0.03771094 = queryNorm
            0.072074346 = fieldWeight in 4119, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              1.0872376 = idf(docFreq=40523, maxDocs=44218)
              0.046875 = fieldNorm(doc=4119)
      0.5 = coord(1/2)
  0.5 = coord(1/2)

Source: Journal of the American Society for Information Science and Technology. 61(2010) no.12, S.2503-2513

Costa Carvalho, A. da; Rossi, C.; Moura, E.S. de; Silva, A.S. da; Fernandes, D.: LePrEF: Learn to precompute evidence fusion for efficient query evaluation (2012) 0.00

6.156463E-4 = product of:
  0.0012312926 = sum of:
    0.0012312926 = product of:
      0.0024625852 = sum of:
        0.0024625852 = weight(_text_:s in 278) [ClassicSimilarity], result of:
          0.0024625852 = score(doc=278,freq=2.0), product of:
            0.04100075 = queryWeight, product of:
              1.0872376 = idf(docFreq=40523, maxDocs=44218)
              0.03771094 = queryNorm
            0.060061958 = fieldWeight in 278, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              1.0872376 = idf(docFreq=40523, maxDocs=44218)
              0.0390625 = fieldNorm(doc=278)
      0.5 = coord(1/2)
  0.5 = coord(1/2)

Source: Journal of the American Society for Information Science and Technology. 63(2012) no.7, S.1383-1397

Search (2 results, page 1 of 1)

Authors