Search (3 results, page 1 of 1)

  • × type_ss:"z"
  1. (2013 ff.) 0.02 
    0.018643405 = product of:
  0.03728681 = sum of:
    0.03728681 = product of:
      0.07457362 = sum of:
        0.07457362 = weight(_text_:22 in 2851) [ClassicSimilarity], result of:
          0.07457362 = score(doc=2851,freq=2.0), product of:
            0.1204662 = queryWeight, product of:
              3.5018296 = idf(docFreq=3622, maxDocs=44218)
              0.034400932 = queryNorm
            0.61904186 = fieldWeight in 2851, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              3.5018296 = idf(docFreq=3622, maxDocs=44218)
              0.125 = fieldNorm(doc=2851)
      0.5 = coord(1/2)
  0.5 = coord(1/2)
    Date
    20. 1.2015 18:30:22
  2. (-2012) 0.02 
    0.018643405 = product of:
  0.03728681 = sum of:
    0.03728681 = product of:
      0.07457362 = sum of:
        0.07457362 = weight(_text_:22 in 5649) [ClassicSimilarity], result of:
          0.07457362 = score(doc=5649,freq=2.0), product of:
            0.1204662 = queryWeight, product of:
              3.5018296 = idf(docFreq=3622, maxDocs=44218)
              0.034400932 = queryNorm
            0.61904186 = fieldWeight in 5649, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              3.5018296 = idf(docFreq=3622, maxDocs=44218)
              0.125 = fieldNorm(doc=5649)
      0.5 = coord(1/2)
  0.5 = coord(1/2)
    Date
    20. 1.2015 18:30:22
  3. International classification (1974 ff) 0.01 
    0.008237598 = product of:
  0.016475197 = sum of:
    0.016475197 = product of:
      0.032950394 = sum of:
        0.032950394 = weight(_text_:m in 574) [ClassicSimilarity], result of:
          0.032950394 = score(doc=574,freq=2.0), product of:
            0.08560495 = queryWeight, product of:
              2.4884486 = idf(docFreq=9980, maxDocs=44218)
              0.034400932 = queryNorm
            0.38491225 = fieldWeight in 574, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              2.4884486 = idf(docFreq=9980, maxDocs=44218)
              0.109375 = fieldNorm(doc=574)
      0.5 = coord(1/2)
  0.5 = coord(1/2)
    Language
    m

Years