Hasiewicz, C.: Online lernen mit 'bibweb - das Lernforum für Bibliotheken' (2002)
0.04
0.036145955 = product of:
0.07229191 = sum of:
0.07229191 = product of:
0.10843786 = sum of:
0.071398646 = weight(_text_:c in 572) [ClassicSimilarity], result of:
0.071398646 = score(doc=572,freq=2.0), product of:
0.15612034 = queryWeight, product of:
3.4494052 = idf(docFreq=3817, maxDocs=44218)
0.045260075 = queryNorm
0.45733082 = fieldWeight in 572, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.4494052 = idf(docFreq=3817, maxDocs=44218)
0.09375 = fieldNorm(doc=572)
0.037039213 = weight(_text_:h in 572) [ClassicSimilarity], result of:
0.037039213 = score(doc=572,freq=2.0), product of:
0.11244635 = queryWeight, product of:
2.4844491 = idf(docFreq=10020, maxDocs=44218)
0.045260075 = queryNorm
0.32939452 = fieldWeight in 572, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
2.4844491 = idf(docFreq=10020, maxDocs=44218)
0.09375 = fieldNorm(doc=572)
0.6666667 = coord(2/3)
0.5 = coord(1/2)
- Source
- BuB. 54(2002) H.5, S.292-293
Hasiewicz, C.: Mehr Mut zu neuen Angeboten : Digitale Dienste in Öffentlichen Bibliotheken - Erwartungen und Möglichkeiten (2005)
0.01
0.0120486505 = product of:
0.024097301 = sum of:
0.024097301 = product of:
0.03614595 = sum of:
0.023799548 = weight(_text_:c in 3069) [ClassicSimilarity], result of:
0.023799548 = score(doc=3069,freq=2.0), product of:
0.15612034 = queryWeight, product of:
3.4494052 = idf(docFreq=3817, maxDocs=44218)
0.045260075 = queryNorm
0.1524436 = fieldWeight in 3069, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.4494052 = idf(docFreq=3817, maxDocs=44218)
0.03125 = fieldNorm(doc=3069)
0.012346405 = weight(_text_:h in 3069) [ClassicSimilarity], result of:
0.012346405 = score(doc=3069,freq=2.0), product of:
0.11244635 = queryWeight, product of:
2.4844491 = idf(docFreq=10020, maxDocs=44218)
0.045260075 = queryNorm
0.10979818 = fieldWeight in 3069, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
2.4844491 = idf(docFreq=10020, maxDocs=44218)
0.03125 = fieldNorm(doc=3069)
0.6666667 = coord(2/3)
0.5 = coord(1/2)
- Source
- BuB. 57(2005) H.5, S.365-376