Search (4 results, page 1 of 1)

  • × language_ss:"e"
  • × classification_ss:"06.35 / Informationsmanagement"
  1. Nicholas, D.: Assessing information needs : tools and techniques (1996) 0.06
    0.056366995 = product of:
      0.11273399 = sum of:
        0.11273399 = sum of:
          0.05090576 = weight(_text_:j in 5941) [ClassicSimilarity], result of:
            0.05090576 = score(doc=5941,freq=2.0), product of:
              0.14500295 = queryWeight, product of:
                3.1774964 = idf(docFreq=5010, maxDocs=44218)
                0.045634337 = queryNorm
              0.35106707 = fieldWeight in 5941, product of:
                1.4142135 = tf(freq=2.0), with freq of:
                  2.0 = termFreq=2.0
                3.1774964 = idf(docFreq=5010, maxDocs=44218)
                0.078125 = fieldNorm(doc=5941)
          0.06182823 = weight(_text_:22 in 5941) [ClassicSimilarity], result of:
            0.06182823 = score(doc=5941,freq=2.0), product of:
              0.15980367 = queryWeight, product of:
                3.5018296 = idf(docFreq=3622, maxDocs=44218)
                0.045634337 = queryNorm
              0.38690117 = fieldWeight in 5941, product of:
                1.4142135 = tf(freq=2.0), with freq of:
                  2.0 = termFreq=2.0
                3.5018296 = idf(docFreq=3622, maxDocs=44218)
                0.078125 = fieldNorm(doc=5941)
      0.5 = coord(1/2)
    
    Date
    26. 2.2008 19:22:51
    Footnote
    Rez. in: Assignation. 14(1997) no.2, S.24 (S. Vogel); Journal of librarianship and information science 30(1998) no.1, S.68 (J. Secker)
  2. Hare, C.E.; McLeod, J.: How to manage records in the e-environment : 2nd ed. (2006) 0.01
    0.008908508 = product of:
      0.017817017 = sum of:
        0.017817017 = product of:
          0.035634033 = sum of:
            0.035634033 = weight(_text_:j in 1749) [ClassicSimilarity], result of:
              0.035634033 = score(doc=1749,freq=2.0), product of:
                0.14500295 = queryWeight, product of:
                  3.1774964 = idf(docFreq=5010, maxDocs=44218)
                  0.045634337 = queryNorm
                0.24574696 = fieldWeight in 1749, product of:
                  1.4142135 = tf(freq=2.0), with freq of:
                    2.0 = termFreq=2.0
                  3.1774964 = idf(docFreq=5010, maxDocs=44218)
                  0.0546875 = fieldNorm(doc=1749)
          0.5 = coord(1/2)
      0.5 = coord(1/2)
    
  3. Taylor, A.G.: ¬The organization of information (1999) 0.01
    0.00636322 = product of:
      0.01272644 = sum of:
        0.01272644 = product of:
          0.02545288 = sum of:
            0.02545288 = weight(_text_:j in 1453) [ClassicSimilarity], result of:
              0.02545288 = score(doc=1453,freq=2.0), product of:
                0.14500295 = queryWeight, product of:
                  3.1774964 = idf(docFreq=5010, maxDocs=44218)
                  0.045634337 = queryNorm
                0.17553353 = fieldWeight in 1453, product of:
                  1.4142135 = tf(freq=2.0), with freq of:
                    2.0 = termFreq=2.0
                  3.1774964 = idf(docFreq=5010, maxDocs=44218)
                  0.0390625 = fieldNorm(doc=1453)
          0.5 = coord(1/2)
      0.5 = coord(1/2)
    
    Footnote
    Rez. in: Knowledge organization 26(1999) no.2, S.106-107 (L.F. Spiteri); JASIS 51(2000) no.5, S.491-492 (J.-E. Mai)
  4. Information ethics : privacy, property, and power (2005) 0.01
    0.0054648947 = product of:
      0.010929789 = sum of:
        0.010929789 = product of:
          0.021859579 = sum of:
            0.021859579 = weight(_text_:22 in 2392) [ClassicSimilarity], result of:
              0.021859579 = score(doc=2392,freq=4.0), product of:
                0.15980367 = queryWeight, product of:
                  3.5018296 = idf(docFreq=3622, maxDocs=44218)
                  0.045634337 = queryNorm
                0.13679022 = fieldWeight in 2392, product of:
                  2.0 = tf(freq=4.0), with freq of:
                    4.0 = termFreq=4.0
                  3.5018296 = idf(docFreq=3622, maxDocs=44218)
                  0.01953125 = fieldNorm(doc=2392)
          0.5 = coord(1/2)
      0.5 = coord(1/2)
    
    Classification
    323.44/5 22 (GBV;LoC)
    DDC
    323.44/5 22 (GBV;LoC)