-
Webb, S.P.: Creating an information service (1996)
0.04
0.04053497 = product of:
0.101337425 = sum of:
0.045174126 = weight(_text_:j in 2437) [ClassicSimilarity], result of:
0.045174126 = score(doc=2437,freq=2.0), product of:
0.12867662 = queryWeight, product of:
3.1774964 = idf(docFreq=5010, maxDocs=44218)
0.04049623 = queryNorm
0.35106707 = fieldWeight in 2437, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.1774964 = idf(docFreq=5010, maxDocs=44218)
0.078125 = fieldNorm(doc=2437)
0.0561633 = weight(_text_:b in 2437) [ClassicSimilarity], result of:
0.0561633 = score(doc=2437,freq=2.0), product of:
0.1434766 = queryWeight, product of:
3.542962 = idf(docFreq=3476, maxDocs=44218)
0.04049623 = queryNorm
0.3914457 = fieldWeight in 2437, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.542962 = idf(docFreq=3476, maxDocs=44218)
0.078125 = fieldNorm(doc=2437)
0.4 = coord(2/5)
- Footnote
- Rez. in: Managing information. 3(1996) no.10, S.50 (J. Balcombe); Library review 46(1997) nos. 5/6. S.451-452 (B. Houston)
-
Crawford, J.: Evaluation of library and information services (2000)
0.01
0.010841791 = product of:
0.054208953 = sum of:
0.054208953 = weight(_text_:j in 835) [ClassicSimilarity], result of:
0.054208953 = score(doc=835,freq=2.0), product of:
0.12867662 = queryWeight, product of:
3.1774964 = idf(docFreq=5010, maxDocs=44218)
0.04049623 = queryNorm
0.4212805 = fieldWeight in 835, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.1774964 = idf(docFreq=5010, maxDocs=44218)
0.09375 = fieldNorm(doc=835)
0.2 = coord(1/5)
-
Crawford, J.: Evaluation of library and information services (1996)
0.01
0.010841791 = product of:
0.054208953 = sum of:
0.054208953 = weight(_text_:j in 1296) [ClassicSimilarity], result of:
0.054208953 = score(doc=1296,freq=2.0), product of:
0.12867662 = queryWeight, product of:
3.1774964 = idf(docFreq=5010, maxDocs=44218)
0.04049623 = queryNorm
0.4212805 = fieldWeight in 1296, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.1774964 = idf(docFreq=5010, maxDocs=44218)
0.09375 = fieldNorm(doc=1296)
0.2 = coord(1/5)