Search (3 results, page 1 of 1)

  • × author_ss:"Mendelsohn, S."
  • × year_i:[1990 TO 2000}
  1. Mendelsohn, S.: ¬The future of librarians (1994) 0.01
    0.012143962 = product of:
      0.024287924 = sum of:
        0.024287924 = product of:
          0.07286377 = sum of:
            0.07286377 = weight(_text_:29 in 8420) [ClassicSimilarity], result of:
              0.07286377 = score(doc=8420,freq=2.0), product of:
                0.15623134 = queryWeight, product of:
                  3.5176873 = idf(docFreq=3565, maxDocs=44218)
                  0.044413086 = queryNorm
                0.46638384 = fieldWeight in 8420, product of:
                  1.4142135 = tf(freq=2.0), with freq of:
                    2.0 = termFreq=2.0
                  3.5176873 = idf(docFreq=3565, maxDocs=44218)
                  0.09375 = fieldNorm(doc=8420)
          0.33333334 = coord(1/3)
      0.5 = coord(1/2)
    
    Source
    Information world review. 1994, no.95, September, S.28-29
  2. Mendelsohn, S.: Should all librarians acquire the skills to educate and train end-users? (1996) 0.01
    0.011449438 = product of:
      0.022898875 = sum of:
        0.022898875 = product of:
          0.068696626 = sum of:
            0.068696626 = weight(_text_:29 in 6596) [ClassicSimilarity], result of:
              0.068696626 = score(doc=6596,freq=4.0), product of:
                0.15623134 = queryWeight, product of:
                  3.5176873 = idf(docFreq=3565, maxDocs=44218)
                  0.044413086 = queryNorm
                0.43971092 = fieldWeight in 6596, product of:
                  2.0 = tf(freq=4.0), with freq of:
                    4.0 = termFreq=4.0
                  3.5176873 = idf(docFreq=3565, maxDocs=44218)
                  0.0625 = fieldNorm(doc=6596)
          0.33333334 = coord(1/3)
      0.5 = coord(1/2)
    
    Date
    25. 2.1997 19:32:29
    Source
    Information world review. 1996, no.113, S.29-30
  3. Mendelsohn, S.: How do you evaluate a database before purchasing it? (1996) 0.01
    0.008095975 = product of:
      0.01619195 = sum of:
        0.01619195 = product of:
          0.04857585 = sum of:
            0.04857585 = weight(_text_:29 in 6908) [ClassicSimilarity], result of:
              0.04857585 = score(doc=6908,freq=2.0), product of:
                0.15623134 = queryWeight, product of:
                  3.5176873 = idf(docFreq=3565, maxDocs=44218)
                  0.044413086 = queryNorm
                0.31092256 = fieldWeight in 6908, product of:
                  1.4142135 = tf(freq=2.0), with freq of:
                    2.0 = termFreq=2.0
                  3.5176873 = idf(docFreq=3565, maxDocs=44218)
                  0.0625 = fieldNorm(doc=6908)
          0.33333334 = coord(1/3)
      0.5 = coord(1/2)
    
    Source
    Information world review. 1996, no.115, S.28-29