Search (2 results, page 1 of 1)
- Did you mean:
- object's%3a%22Aleph 500%22 2
- objects%3a%22Aleph 500%22 2
-
Historical aspects of cataloging and classification : Pt. 1 (2003)
0.06
0.062317647 = product of: 0.124635294 = sum of: 0.124635294 = product of: 0.24927059 = sum of: 0.24927059 = weight(_text_:500 in 4057) [ClassicSimilarity], result of: 0.24927059 = score(doc=4057,freq=2.0), product of: 0.3075407 = queryWeight, product of: 6.113391 = idf(docFreq=265, maxDocs=44218) 0.050306078 = queryNorm 0.81052876 = fieldWeight in 4057, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 6.113391 = idf(docFreq=265, maxDocs=44218) 0.09375 = fieldNorm(doc=4057) 0.5 = coord(1/2) 0.5 = coord(1/2)
- Footnote
- Also published as NIST special publication; 500-251(?) bei Haworth Press
-
Riplinger, T.: ¬Die Bedeutung der Methode Eppelsheimer für Theorie und Praxis der bibliothekarischen und der dokumentarischen Sacherschließung (2004)
0.01
0.013631558 = product of: 0.027263116 = sum of: 0.027263116 = product of: 0.054526232 = sum of: 0.054526232 = weight(_text_:22 in 2521) [ClassicSimilarity], result of: 0.054526232 = score(doc=2521,freq=2.0), product of: 0.17616332 = queryWeight, product of: 3.5018296 = idf(docFreq=3622, maxDocs=44218) 0.050306078 = queryNorm 0.30952093 = fieldWeight in 2521, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 3.5018296 = idf(docFreq=3622, maxDocs=44218) 0.0625 = fieldNorm(doc=2521) 0.5 = coord(1/2) 0.5 = coord(1/2)
- Date
- 22. 3.2008 13:33:51