Search (2 results, page 1 of 1)

Did you mean:
precises%3a%2fdocuments %2f author %26 descriptive cataloguing %2f rules%3a anglo %2f american cataloguing rules %2f 2nd ed.%22 2
precises%3a%2f_documents %2f author %26 descriptive cataloguing %2f rules%3a anglo %2f american cataloguing rules %2f 2nd ed.%22 2
precises%3a%2fdocuments %2f author %26 descriptive cataloguing %2f rules%3a angle %2f american cataloguing rules %2f 2nd ed.%22 2
precises%3a%2fdocuments %2f author %26 deskriptive cataloguing %2f rules%3a anglo %2f american cataloguing rules %2f 2nd ed.%22 2
precises%3a%2f_documents %2f author %26 deskriptive cataloguing %2f rules%3a anglo %2f american cataloguing rules %2f 2nd ed.%22 2

Kessler, M.M.: Bibliographic coupling between scientific papers (1963) 0.00

0.004121224 = product of:
  0.06593958 = sum of:
    0.06593958 = weight(_text_:american in 4993) [ClassicSimilarity], result of:
      0.06593958 = score(doc=4993,freq=2.0), product of:
        0.10940785 = queryWeight, product of:
          3.4093587 = idf(docFreq=3973, maxDocs=44218)
          0.032090448 = queryNorm
        0.60269517 = fieldWeight in 4993, product of:
          1.4142135 = tf(freq=2.0), with freq of:
            2.0 = termFreq=2.0
          3.4093587 = idf(docFreq=3973, maxDocs=44218)
          0.125 = fieldNorm(doc=4993)
  0.0625 = coord(1/16)

Source: American documentation. 14(1963), S.10-25

Kessler, M.M.: Comparison of results of bibliographic coupling and analytic subject indexing (1965) 0.00

0.004121224 = product of:
  0.06593958 = sum of:
    0.06593958 = weight(_text_:american in 7693) [ClassicSimilarity], result of:
      0.06593958 = score(doc=7693,freq=2.0), product of:
        0.10940785 = queryWeight, product of:
          3.4093587 = idf(docFreq=3973, maxDocs=44218)
          0.032090448 = queryNorm
        0.60269517 = fieldWeight in 7693, product of:
          1.4142135 = tf(freq=2.0), with freq of:
            2.0 = termFreq=2.0
          3.4093587 = idf(docFreq=3973, maxDocs=44218)
          0.125 = fieldNorm(doc=7693)
  0.0625 = coord(1/16)

Source: American documentation. 16(1965), S.223-233