Search (2 results, page 1 of 1)
- Did you mean:
- rswk_00%3a%22Internet %2f suchmaschinen %2f wegweiser %28%c3%9612%29%22 2
- rswk_00%3a%22Internet %2f suchmaschinen %2f wegweiser %28%c3%9600%29%22 2
- rswk_00%3a%22Internet %2f suchmaschinen %2f wegweisers %28%c3%9612%29%22 2
- rswk_00%3a%22Internet %2f suchmaschinen %2f wegweise %28%c3%9612%29%22 2
- rswk_00%3a%22Internet %2f suchmaschinen %2f wegweiser %28%c3%9617%29%22 2
-
Tennis, J.T.: 6th Annual Open Forum on Metadata Registries : Santa Fe, New Mexico, USA, Jan 20-24, 2003 (2002)
0.01
0.0076535735 = product of: 0.04592144 = sum of: 0.04592144 = product of: 0.1148036 = sum of: 0.05844588 = weight(_text_:28 in 1856) [ClassicSimilarity], result of: 0.05844588 = score(doc=1856,freq=2.0), product of: 0.12305808 = queryWeight, product of: 3.5822632 = idf(docFreq=3342, maxDocs=44218) 0.03435205 = queryNorm 0.4749455 = fieldWeight in 1856, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 3.5822632 = idf(docFreq=3342, maxDocs=44218) 0.09375 = fieldNorm(doc=1856) 0.056357715 = weight(_text_:29 in 1856) [ClassicSimilarity], result of: 0.056357715 = score(doc=1856,freq=2.0), product of: 0.12083977 = queryWeight, product of: 3.5176873 = idf(docFreq=3565, maxDocs=44218) 0.03435205 = queryNorm 0.46638384 = fieldWeight in 1856, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 3.5176873 = idf(docFreq=3565, maxDocs=44218) 0.09375 = fieldNorm(doc=1856) 0.4 = coord(2/5) 0.16666667 = coord(1/6)
- Date
- 6. 1.1997 18:30:28
- Source
- Knowledge organization. 29(2002) nos.3/4, S.234-235
-
Tennis, J.T.: Data collection for controlled vocabulary interoperability : Dublin core audience element (2003)
0.00
7.827461E-4 = product of: 0.0046964767 = sum of: 0.0046964767 = product of: 0.023482382 = sum of: 0.023482382 = weight(_text_:29 in 1253) [ClassicSimilarity], result of: 0.023482382 = score(doc=1253,freq=2.0), product of: 0.12083977 = queryWeight, product of: 3.5176873 = idf(docFreq=3565, maxDocs=44218) 0.03435205 = queryNorm 0.19432661 = fieldWeight in 1253, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 3.5176873 = idf(docFreq=3565, maxDocs=44218) 0.0390625 = fieldNorm(doc=1253) 0.2 = coord(1/5) 0.16666667 = coord(1/6)
- Source
- Bulletin of the American Society for Information Science. 29(2003) no.2, S.20-23