Search (2 results, page 1 of 1)

Did you mean:
rswk_00%3a%22Museum %2f informationsmanagement %28BVB%29%22 2
rswk_00%3a%22Museum %2f informationsmanagements %28BVB%29%22 2
rswk_00%3a%22Museum %2f informationsmanagemsnt %28BVB%29%22 2
rswk_00%3a%22Museum %2f informationsmaganement %28BVB%29%22 2
rswk_00%3a%22Museum %2f informationsmanagementan %28BVB%29%22 2

Zhonghong, W.; Chaudhry, A.S.; Khoo, C.: Potential and prospects of taxonomies for content organization (2006) 0.00

0.0032101942 = product of:
  0.012840777 = sum of:
    0.012840777 = product of:
      0.03852233 = sum of:
        0.03852233 = weight(_text_:29 in 169) [ClassicSimilarity], result of:
          0.03852233 = score(doc=169,freq=2.0), product of:
            0.14159642 = queryWeight, product of:
              3.5176873 = idf(docFreq=3565, maxDocs=44218)
              0.040252704 = queryNorm
            0.27205724 = fieldWeight in 169, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              3.5176873 = idf(docFreq=3565, maxDocs=44218)
              0.0546875 = fieldNorm(doc=169)
      0.33333334 = coord(1/3)
  0.25 = coord(1/4)

Date: 11. 3.2007 14:20:29

Wang, Z.; Chaudhry, A.S.; Khoo, C.S.G.: Using classification schemes and thesauri to build an organizational taxonomy for organizing content and aiding navigation (2008) 0.00

0.0018178953 = product of:
  0.0072715813 = sum of:
    0.0072715813 = product of:
      0.021814743 = sum of:
        0.021814743 = weight(_text_:22 in 2346) [ClassicSimilarity], result of:
          0.021814743 = score(doc=2346,freq=2.0), product of:
            0.14095812 = queryWeight, product of:
              3.5018296 = idf(docFreq=3622, maxDocs=44218)
              0.040252704 = queryNorm
            0.15476047 = fieldWeight in 2346, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              3.5018296 = idf(docFreq=3622, maxDocs=44218)
              0.03125 = fieldNorm(doc=2346)
      0.33333334 = coord(1/3)
  0.25 = coord(1/4)

Date: 7.11.2008 15:22:04

Search (2 results, page 1 of 1)

Authors