Search (3 results, page 1 of 1)

  • × theme_ss:"Sprachretrieval"
  • × year_i:[2000 TO 2010}
  1. Voorhees, E.M.: Question answering in TREC (2005) 0.01
    0.008859639 = product of:
      0.039868373 = sum of:
        0.023921024 = product of:
          0.047842048 = sum of:
            0.047842048 = weight(_text_:29 in 6487) [ClassicSimilarity], result of:
              0.047842048 = score(doc=6487,freq=2.0), product of:
                0.102580845 = queryWeight, product of:
                  3.5176873 = idf(docFreq=3565, maxDocs=44218)
                  0.029161446 = queryNorm
                0.46638384 = fieldWeight in 6487, product of:
                  1.4142135 = tf(freq=2.0), with freq of:
                    2.0 = termFreq=2.0
                  3.5176873 = idf(docFreq=3565, maxDocs=44218)
                  0.09375 = fieldNorm(doc=6487)
          0.5 = coord(1/2)
        0.01594735 = product of:
          0.047842048 = sum of:
            0.047842048 = weight(_text_:29 in 6487) [ClassicSimilarity], result of:
              0.047842048 = score(doc=6487,freq=2.0), product of:
                0.102580845 = queryWeight, product of:
                  3.5176873 = idf(docFreq=3565, maxDocs=44218)
                  0.029161446 = queryNorm
                0.46638384 = fieldWeight in 6487, product of:
                  1.4142135 = tf(freq=2.0), with freq of:
                    2.0 = termFreq=2.0
                  3.5176873 = idf(docFreq=3565, maxDocs=44218)
                  0.09375 = fieldNorm(doc=6487)
          0.33333334 = coord(1/3)
      0.22222222 = coord(2/9)
    
    Date
    29. 3.1996 18:16:49
  2. Ferret, O.; Grau, B.; Hurault-Plantet, M.; Illouz, G.; Jacquemin, C.; Monceaux, L.; Robba, I.; Vilnat, A.: How NLP can improve question answering (2002) 0.00
    0.0044298195 = product of:
      0.019934187 = sum of:
        0.011960512 = product of:
          0.023921024 = sum of:
            0.023921024 = weight(_text_:29 in 1850) [ClassicSimilarity], result of:
              0.023921024 = score(doc=1850,freq=2.0), product of:
                0.102580845 = queryWeight, product of:
                  3.5176873 = idf(docFreq=3565, maxDocs=44218)
                  0.029161446 = queryNorm
                0.23319192 = fieldWeight in 1850, product of:
                  1.4142135 = tf(freq=2.0), with freq of:
                    2.0 = termFreq=2.0
                  3.5176873 = idf(docFreq=3565, maxDocs=44218)
                  0.046875 = fieldNorm(doc=1850)
          0.5 = coord(1/2)
        0.007973675 = product of:
          0.023921024 = sum of:
            0.023921024 = weight(_text_:29 in 1850) [ClassicSimilarity], result of:
              0.023921024 = score(doc=1850,freq=2.0), product of:
                0.102580845 = queryWeight, product of:
                  3.5176873 = idf(docFreq=3565, maxDocs=44218)
                  0.029161446 = queryNorm
                0.23319192 = fieldWeight in 1850, product of:
                  1.4142135 = tf(freq=2.0), with freq of:
                    2.0 = termFreq=2.0
                  3.5176873 = idf(docFreq=3565, maxDocs=44218)
                  0.046875 = fieldNorm(doc=1850)
          0.33333334 = coord(1/3)
      0.22222222 = coord(2/9)
    
    Source
    Knowledge organization. 29(2002) nos.3/4, S.135-155
  3. Rösener, C.: ¬Die Stecknadel im Heuhaufen : Natürlichsprachlicher Zugang zu Volltextdatenbanken (2005) 0.00
    0.002953213 = product of:
      0.013289458 = sum of:
        0.007973675 = product of:
          0.01594735 = sum of:
            0.01594735 = weight(_text_:29 in 548) [ClassicSimilarity], result of:
              0.01594735 = score(doc=548,freq=2.0), product of:
                0.102580845 = queryWeight, product of:
                  3.5176873 = idf(docFreq=3565, maxDocs=44218)
                  0.029161446 = queryNorm
                0.15546128 = fieldWeight in 548, product of:
                  1.4142135 = tf(freq=2.0), with freq of:
                    2.0 = termFreq=2.0
                  3.5176873 = idf(docFreq=3565, maxDocs=44218)
                  0.03125 = fieldNorm(doc=548)
          0.5 = coord(1/2)
        0.0053157834 = product of:
          0.01594735 = sum of:
            0.01594735 = weight(_text_:29 in 548) [ClassicSimilarity], result of:
              0.01594735 = score(doc=548,freq=2.0), product of:
                0.102580845 = queryWeight, product of:
                  3.5176873 = idf(docFreq=3565, maxDocs=44218)
                  0.029161446 = queryNorm
                0.15546128 = fieldWeight in 548, product of:
                  1.4142135 = tf(freq=2.0), with freq of:
                    2.0 = termFreq=2.0
                  3.5176873 = idf(docFreq=3565, maxDocs=44218)
                  0.03125 = fieldNorm(doc=548)
          0.33333334 = coord(1/3)
      0.22222222 = coord(2/9)
    
    Date
    29. 3.2009 11:11:45