Search (2 results, page 1 of 1)

Did you mean:
sbss%3a%22nd 5%22 2

Glänzel, W.: Visual bibliometrics : eine visuelle Oberfläche zur Erweiterung der Nutzungsmöglichkeiten bibliographischer Datenbanken (1996) 0.01

0.008602629 = product of:
  0.017205259 = sum of:
    0.017205259 = product of:
      0.034410518 = sum of:
        0.034410518 = weight(_text_:5 in 6110) [ClassicSimilarity], result of:
          0.034410518 = score(doc=6110,freq=2.0), product of:
            0.15247129 = queryWeight, product of:
              2.9180994 = idf(docFreq=6494, maxDocs=44218)
              0.052250203 = queryNorm
            0.22568524 = fieldWeight in 6110, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              2.9180994 = idf(docFreq=6494, maxDocs=44218)
              0.0546875 = fieldNorm(doc=6110)
      0.5 = coord(1/2)
  0.5 = coord(1/2)

Source: Herausforderungen an die Informationswirtschaft: Informationsverdichtung, Informationsbewertung und Datenvisualisierung. Proceedings des 5. Internationalen Symposiums für Informationswissenschaft (ISI'96), Humboldt-Universität zu Berlin, 17.-19. Oktober 1996. Hrsg.: J. Krause u.a

Zhang, L.; Rousseau, R.; Glänzel, W.: Diversity of references as an indicator of the interdisciplinarity of journals : taking similarity between subject fields into account (2016) 0.01

0.0061447355 = product of:
  0.012289471 = sum of:
    0.012289471 = product of:
      0.024578942 = sum of:
        0.024578942 = weight(_text_:5 in 2902) [ClassicSimilarity], result of:
          0.024578942 = score(doc=2902,freq=2.0), product of:
            0.15247129 = queryWeight, product of:
              2.9180994 = idf(docFreq=6494, maxDocs=44218)
              0.052250203 = queryNorm
            0.16120374 = fieldWeight in 2902, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              2.9180994 = idf(docFreq=6494, maxDocs=44218)
              0.0390625 = fieldNorm(doc=2902)
      0.5 = coord(1/2)
  0.5 = coord(1/2)

Source: Journal of the Association for Information Science and Technology. 67(2016) no.5, S.1257-1265

Search (2 results, page 1 of 1)

Authors

Years

Languages