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Tseng, Y.-H.: Solving vocabulary problems with interactive query expansion (1998)
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Lu, S.-j.: Bibliographic control in a national bibliographic centre (1996)
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- Bulletin of the Library Association of China. 1996, no.57, Dec., S.9-33
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Fu, R.-X.: ¬The comparison between Chinese and Western bibliography (1996)
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- Bulletin of the Library Association of China. 1996, no.57, Dec., S.47-54
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Zeng, M.L.; Fan, W.: SKOS and its application in transferring traditional thesauri into networked knowledge organization systems (2008)
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Lee, Y.-R.: ¬A study on the conditions of using OPAC access points and subject searching by users (1997)
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- Bulletin of library and information science. 1997, no.22, S.39-55
-
Yi, H.; Shubai, L.: Application of classification in information organization under the networking environment (1998)
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- Journal of the China Society for Scientific and Technical Information. 17(1998) no.1, S.19-22
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Lin, W.-Y.C.: ¬The concept and applications of faceted classifications (2006)
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Pu, H.-T.: Exploration of personalized information service for OPAC (1997)
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