Search (2 results, page 1 of 1)
- Did you mean:
- sbss%3a%22S 132%22 2
-
Schmitz-Esser, W.: Thesauri facing new challenges (1990)
0.04
0.042379204 = product of: 0.08475841 = sum of: 0.08475841 = product of: 0.16951682 = sum of: 0.16951682 = weight(_text_:132 in 2218) [ClassicSimilarity], result of: 0.16951682 = score(doc=2218,freq=2.0), product of: 0.33069554 = queryWeight, product of: 6.627983 = idf(docFreq=158, maxDocs=44218) 0.04989384 = queryNorm 0.5126069 = fieldWeight in 2218, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 6.627983 = idf(docFreq=158, maxDocs=44218) 0.0546875 = fieldNorm(doc=2218) 0.5 = coord(1/2) 0.5 = coord(1/2)
- Source
- International classification. 17(1990), S.129-132
-
Schmitz-Esser, W.: Thesaurus and beyond : an advanced formula for linguistic engineering and information retrieval (1999)
0.01
0.01013989 = product of: 0.02027978 = sum of: 0.02027978 = product of: 0.04055956 = sum of: 0.04055956 = weight(_text_:22 in 4116) [ClassicSimilarity], result of: 0.04055956 = score(doc=4116,freq=2.0), product of: 0.17471974 = queryWeight, product of: 3.5018296 = idf(docFreq=3622, maxDocs=44218) 0.04989384 = queryNorm 0.23214069 = fieldWeight in 4116, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = termFreq=2.0 3.5018296 = idf(docFreq=3622, maxDocs=44218) 0.046875 = fieldNorm(doc=4116) 0.5 = coord(1/2) 0.5 = coord(1/2)
- Source
- Knowledge organization. 26(1999) no.1, S.10-22