-
Bourdon, F.: Modeliser les données d'autorité (2001)
0.01
0.008935547 = product of:
0.044677734 = sum of:
0.044677734 = product of:
0.1340332 = sum of:
0.1340332 = weight(_text_:f in 3937) [ClassicSimilarity], result of:
0.1340332 = score(doc=3937,freq=4.0), product of:
0.15372707 = queryWeight, product of:
3.985786 = idf(docFreq=2232, maxDocs=44218)
0.03856882 = queryNorm
0.87189066 = fieldWeight in 3937, product of:
2.0 = tf(freq=4.0), with freq of:
4.0 = termFreq=4.0
3.985786 = idf(docFreq=2232, maxDocs=44218)
0.109375 = fieldNorm(doc=3937)
0.33333334 = coord(1/3)
0.2 = coord(1/5)
- Language
- f
-
Bélair, J.-A.; Bourdon, F.; Mingam, M.: ¬Le Répertoire de vedettes-matière et RAMEAU : deux langages d'indexation en français : un luxe nécessaire (2005)
0.00
0.004690186 = product of:
0.02345093 = sum of:
0.02345093 = product of:
0.070352785 = sum of:
0.070352785 = weight(_text_:f in 4359) [ClassicSimilarity], result of:
0.070352785 = score(doc=4359,freq=6.0), product of:
0.15372707 = queryWeight, product of:
3.985786 = idf(docFreq=2232, maxDocs=44218)
0.03856882 = queryNorm
0.45764732 = fieldWeight in 4359, product of:
2.4494898 = tf(freq=6.0), with freq of:
6.0 = termFreq=6.0
3.985786 = idf(docFreq=2232, maxDocs=44218)
0.046875 = fieldNorm(doc=4359)
0.33333334 = coord(1/3)
0.2 = coord(1/5)
- Language
- f
- Series
- 139 SI - Classification et Indexation avec Catalogage ; 145-F
-
Bourdon, F.: Modeling authority data for libraries, archives, and museums : a project in progress at AFNOR (2004)
0.00
0.0036105064 = product of:
0.018052531 = sum of:
0.018052531 = product of:
0.054157592 = sum of:
0.054157592 = weight(_text_:f in 5690) [ClassicSimilarity], result of:
0.054157592 = score(doc=5690,freq=2.0), product of:
0.15372707 = queryWeight, product of:
3.985786 = idf(docFreq=2232, maxDocs=44218)
0.03856882 = queryNorm
0.35229704 = fieldWeight in 5690, product of:
1.4142135 = tf(freq=2.0), with freq of:
2.0 = termFreq=2.0
3.985786 = idf(docFreq=2232, maxDocs=44218)
0.0625 = fieldNorm(doc=5690)
0.33333334 = coord(1/3)
0.2 = coord(1/5)