Search (7 results, page 1 of 1)

0.009594754 = product of:
  0.057568524 = sum of:
    0.057568524 = weight(_text_:b in 4782) [ClassicSimilarity], result of:
      0.057568524 = score(doc=4782,freq=4.0), product of:
        0.14855953 = queryWeight, product of:
          3.542962 = idf(docFreq=3476, maxDocs=44218)
          0.041930884 = queryNorm
        0.3875115 = fieldWeight in 4782, product of:
          2.0 = tf(freq=4.0), with freq of:
            4.0 = termFreq=4.0
          3.542962 = idf(docFreq=3476, maxDocs=44218)
          0.0546875 = fieldNorm(doc=4782)
  0.16666667 = coord(1/6)

Abstract

In diesem Dokument sollen Begriffe, Prinzipien und Methoden vorgestellt werden, die sich als hilfreich bei der Erstellung von Semantic Web konformen Repräsentationen von Wissensorganisationssystemen (KOS) erwiesen haben, wie z. B. Thesauri und Klassifikationssysteme. Das Dokument richtet sich an Organisationen wie z. B. Bibliotheken, die ihre traditionellen Wissensorganisationssysteme im Rahmen des Semantic Web veröffentlichen wollen. Die in diesem Dokument beschriebenen Vorgehensweisen und Prinzipien sind nicht als normativ anzusehen. Sie sollen nur dabei helfen, von bisher gemachten Erfahrungen zu profitieren und einen leichteren Einstieg in die wichtigsten Begriffichkeiten und Techniken des Semantic Web zu bekommen. An vielen Stellen wird zudem auf weiterführende Literatur zum Thema und auf relevante Standards und Spezifikationen aus dem Bereich des Semantic Web hingewiesen.

0.0058152988 = product of:
  0.03489179 = sum of:
    0.03489179 = weight(_text_:b in 241) [ClassicSimilarity], result of:
      0.03489179 = score(doc=241,freq=2.0), product of:
        0.14855953 = queryWeight, product of:
          3.542962 = idf(docFreq=3476, maxDocs=44218)
          0.041930884 = queryNorm
        0.23486741 = fieldWeight in 241, product of:
          1.4142135 = tf(freq=2.0), with freq of:
            2.0 = termFreq=2.0
          3.542962 = idf(docFreq=3476, maxDocs=44218)
          0.046875 = fieldNorm(doc=241)
  0.16666667 = coord(1/6)

Abstract

The semantic heterogeneity presented by Web information in the Agricultural domain presents tremendous information retrieval challenges. This article presents work taking place at the Food and Agriculture Organizations (FAO) which addresses this challenge. Based on the analysis of resources in the domain of agriculture, this paper proposes (a) an application profile (AP) for dealing with the problem of heterogeneity originating from differences in terminologies, domain coverage, and domain modelling, and (b) a root application ontology (AAO) based on the application profile which can serve as a basis for extending knowledge of the domain. The paper explains how even a small investment in the enhancement of relations between vocabularies, both metadata and domain-specific, yields a relatively large return on investment.

0.0058152988 = product of:
  0.03489179 = sum of:
    0.03489179 = weight(_text_:b in 557) [ClassicSimilarity], result of:
      0.03489179 = score(doc=557,freq=2.0), product of:
        0.14855953 = queryWeight, product of:
          3.542962 = idf(docFreq=3476, maxDocs=44218)
          0.041930884 = queryNorm
        0.23486741 = fieldWeight in 557, product of:
          1.4142135 = tf(freq=2.0), with freq of:
            2.0 = termFreq=2.0
          3.542962 = idf(docFreq=3476, maxDocs=44218)
          0.046875 = fieldNorm(doc=557)
  0.16666667 = coord(1/6)

0.0033922575 = product of:
  0.020353545 = sum of:
    0.020353545 = weight(_text_:b in 5903) [ClassicSimilarity], result of:
      0.020353545 = score(doc=5903,freq=2.0), product of:
        0.14855953 = queryWeight, product of:
          3.542962 = idf(docFreq=3476, maxDocs=44218)
          0.041930884 = queryNorm
        0.13700598 = fieldWeight in 5903, product of:
          1.4142135 = tf(freq=2.0), with freq of:
            2.0 = termFreq=2.0
          3.542962 = idf(docFreq=3476, maxDocs=44218)
          0.02734375 = fieldNorm(doc=5903)
  0.16666667 = coord(1/6)

0.003313949 = product of:
  0.019883694 = sum of:
    0.019883694 = product of:
      0.03976739 = sum of:
        0.03976739 = weight(_text_:22 in 4184) [ClassicSimilarity], result of:
          0.03976739 = score(doc=4184,freq=2.0), product of:
            0.1468348 = queryWeight, product of:
              3.5018296 = idf(docFreq=3622, maxDocs=44218)
              0.041930884 = queryNorm
            0.2708308 = fieldWeight in 4184, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              3.5018296 = idf(docFreq=3622, maxDocs=44218)
              0.0546875 = fieldNorm(doc=4184)
      0.5 = coord(1/2)
  0.16666667 = coord(1/6)

Date

22. 1.2011 10:38:28

0.003313949 = product of:
  0.019883694 = sum of:
    0.019883694 = product of:
      0.03976739 = sum of:
        0.03976739 = weight(_text_:22 in 759) [ClassicSimilarity], result of:
          0.03976739 = score(doc=759,freq=2.0), product of:
            0.1468348 = queryWeight, product of:
              3.5018296 = idf(docFreq=3622, maxDocs=44218)
              0.041930884 = queryNorm
            0.2708308 = fieldWeight in 759, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              3.5018296 = idf(docFreq=3622, maxDocs=44218)
              0.0546875 = fieldNorm(doc=759)
      0.5 = coord(1/2)
  0.16666667 = coord(1/6)

Date

11. 5.2013 19:22:18

0.003313949 = product of:
  0.019883694 = sum of:
    0.019883694 = product of:
      0.03976739 = sum of:
        0.03976739 = weight(_text_:22 in 3283) [ClassicSimilarity], result of:
          0.03976739 = score(doc=3283,freq=2.0), product of:
            0.1468348 = queryWeight, product of:
              3.5018296 = idf(docFreq=3622, maxDocs=44218)
              0.041930884 = queryNorm
            0.2708308 = fieldWeight in 3283, product of:
              1.4142135 = tf(freq=2.0), with freq of:
                2.0 = termFreq=2.0
              3.5018296 = idf(docFreq=3622, maxDocs=44218)
              0.0546875 = fieldNorm(doc=3283)
      0.5 = coord(1/2)
  0.16666667 = coord(1/6)